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Top Forums Shell Programming and Scripting How to convert hex numbers to decimal ? Post 302297421 by jack2 on Friday 13th of March 2009 10:28:51 AM
Old 03-13-2009
Quote:
Originally Posted by daptal
To convert hex to decimal try using bc
Eg:- bc
ibase=16
3039
12345

and the second part of conversion of seconds to min 1 min = 60 sec so if $x sec is given $x/60 will give u min and so on

similarly for bytes use 1000 or 1024 as a standard
Thanks for your excellent solution.
Unfortunately neither my Linux embedded machine not Nokia Tablet come
with bc installable package.
So I have to look for another shell based only solution.

Great idea is to use in bc - input and out base (there is a number of good bc calculator examples I learned from Google).

For seconds conversion it would be nice to use timestamp, datetime
to read seconds as input and output result in one of available formats,
the same with bytes to Mbytes, Gbytes conversion,
as I need to write another conversion script for use in main script.

minutes = seconds (mod 60)

expr 5 % 3
2
works fine for constants

didn't work for seconds as variable
/="slash-equal" (divide variable by a constant)
%="mod-equal" (remainder of dividing variable by a constant)
It started to work for me as in the following example
# If you need a random int within a certain range, use the 'modulo' operator.
# This returns the remainder of a division operation.

RANGE=500

echo

number=$RANDOM
let "number %= $RANGE"
# ^^
echo "Random number less than $RANGE --- $number"
-
for remainder
seconds %= seconds
for minutes
minutes /= seconds
..

a=9
let "a %= 4"
echo $a
1

so a mod(4) = 1, exactly as 9 = 2*4 + 1 -

for conversion of seconds I would like to use epoch time
and date +%s
I get 95958

should be

The current Unix epoch time is 1236954365


-
-
What is epoch time?

The Unix epoch (or Unix time or POSIX time or Unix timestamp) is the number of seconds that have elapsed since January 1, 1970 (midnight UTC/GMT), not counting leap seconds. The epoch timestamp 0 can be written in ISO 8601 format as: 1970-01-01T00:00:00Z. One epoch hour is 3600 seconds, one epoch day is 86400 seconds long, leap seconds are not calculated. Many Unix systems store epoch dates as a signed 32-bit integer, which might cause problems on January 19, 2038 (known as the Year 2038 problem or Y2038).

Human readable time Seconds 1 minute60 seconds 1 hour3600 seconds 1 day86400 seconds 1 week604800 seconds 1 month (30.44 days) 2629743 seconds 1 year (365.24 days) 31556926 seconds

Jack
 

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datetime(3)						     Library Functions Manual						       datetime(3)

NAME
datetime - convert between TAI labels and seconds SYNTAX
#include <datetime.h> void datetime_tai(&dt,t); datetime_sec datetime_untai(&dt); struct datetime dt; datetime_sec t; DESCRIPTION
International Atomic Time, TAI, is the fundamental unit for time measurements. TAI has one label for every second of real time, without complications such as leap seconds. A struct datetime variable, such as dt, stores a TAI label. dt.year is the year number minus 1900; dt.mon is the month number, from 0 (January) through 11 (December); dt.mday is the day of the month, from 1 through 31; dt.hour is the hour, from 0 through 23; dt.min is the minute, from 0 through 59; dt.sec is the second, from 0 through 59; dt.wday is the day of the week, from 0 (Sunday) through 6 (Saturday); dt.yday is the day of the year, from 0 through 365. The datetime library supports more convenient TAI manipulation with the datetime_sec type. A datetime_sec value, such as t, is an integer referring to the tth second after the beginning of 1970 TAI. The first second of 1970 TAI was 0; the next second was 1; the last second of 1969 TAI was -1. The difference between two datetime_sec values is a number of real-time seconds. datetime_tai converts a datetime_sec to a TAI label. datetime_untai reads a TAI label (specifically dt.year, dt.mon, dt.mday, dt.hour, dt.min, and dt.sec) and returns a datetime_sec. SEE ALSO
now(3) datetime(3)
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