03-12-2009
How to sort a set of files by date in a directory?
hi there,
I have a directory which contents I can parse dynamically. I end up with a file list. I then want to display those files sorted by date, oldest files first. I have very very little PERL experience...Would anyone know how to do that ? Thanks in advance.
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LEARN ABOUT SUSE
exiqsumm
EXIQSUMM(8) System Manager's Manual EXIQSUMM(8)
NAME
exiqsumm - Summarising the queue
SYNOPSIS
exiqsumm [-a] [-c]
DESCRIPTION
The exiqsumm utility is a Perl script which reads the output of exim -bp and produces a summary of the messages on the queue. Thus, you
use it by running a command such as
exim -bp | exiqsumm
The output consists of one line for each domain that has messages waiting for it, as in the following example:
3 2322 74m 66m msn.com.example
This lists the number of messages for the domain, their total volume, and the length of time that the oldest and the newest messages have
been waiting. By default the output is sorted on the domain name, but exiqsumm has the options -a and -c, which cause the output to be
sorted by oldest message and by count of messages, respectively.
The output of exim -bp contains the original addresses in the message, so this also applies to the output from exiqsumm. No domains from
addresses generated by aliasing or forwarding are included (unless the "one_time" option of the redirect router has been used to convert
them into 'top level' addresses).
BUGS
This manual page needs a major re-work. If somebody knows better groff than us and has more experience in writing manual pages, any patches
would be greatly appreciated.
SEE ALSO
exim(8), /usr/share/doc/exim4-base/
AUTHOR
This manual page was stitched together from spec.txt by Andreas Metzler <ametzler at downhill.at.eu.org>, for the Debian GNU/Linux system
(but may be used by others).
March 26, 2003 EXIQSUMM(8)