Dear friends
I have a bit basic doubts in pointers and the structures inter relationships.
the first one.
static struct apvt {
int dead;
int pending;
int abouttograb;
}*agents=NULL;
what agents pointer is... (1 Reply)
void main()
{
int a={1,2,3,4,5,6,7,8,9,10};
int *p=a;
int *q=&a;
cout<<q-p+1<<endl;
}
The output is 10, how?
if we give cout<<q it will print the address, value won't print....
if we give cout<<p it will print the address, value won't print....
p has the base addr; q... (1 Reply)
Hi,
I am trying to divide my input to different type of out puts for some other use.
ex: logical_name : jkl00001
expected out put : model=jkl and num=00001
here is the code i actually written
/*******************************************************************/
void... (11 Replies)
If one wants to get a start address of a array or a string or a block of memory via a function, there are at least two methods to achieve it:
(1) one is to pass a pointer-to-pointer parameter, like:
int my_malloc(int size, char **pmem)
{
*pmem=(char *)malloc(size);
if(*pmem==NULL)... (11 Replies)
I have a file that reads File (X.txt)
Contents of record 1:
rdrDESTINATION_ADDRESS (String) "91 971502573813"
rdrDESTINATION_IMSI (String) "000000000000000"
rdrORIGINATING_ADDRESS (String) "d0 movies"
rdrORIGINATING_IMSI (String) "000000000000000"
rdrTRAFFIC_EVENT_TIME... (0 Replies)
hi guys!
Is there such a thing as double void pointer dynamic allocation?
And if so is it something like this?
int n;
void** a;
a=malloc(n*sizeof(void*)); (12 Replies)
This code is to print out the program name and arguments list one by one:
1 #include<stdio.h>
2
3 void main(int argc, char *argv)
4 {
5 int iCount = 0;
6 while (iCount < argc) {
7 printf("argc:%d\t%s\n",iCount, argv);
8 ... (14 Replies)
Here are two programs that pass a pointer to a variable but behave differently. Shouldnt the i in second program be 0 after the function call?
#include<stdio.h>
void changeI(int *i)
{
*i = 10;
}
int main(void)
{
int i=5;
printf("%d before\n", i);
changeI(&i);
printf("%d... (1 Reply)