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Full Discussion: Converting Perl code to shell
Top Forums Shell Programming and Scripting Converting Perl code to shell Post 302292910 by zainravi on Monday 2nd of March 2009 01:54:09 AM
Old 03-02-2009
Converting Perl code to shell
I have a perl code that runs like

Code I
Code:
sub p
{
   if ($d >= $D) {return}

   printf "%3s"x$d++," ";
   printf "%s%s\n",$_[0],$h{$_[0]}?" ** ":"";

   if (!$h{$_[0]})
   {
      $h{$_[0]}=1;
      map {p($_)} @{$s{$_[0]}}
   }
   $d--
}

($Set,$Job,$Num,$D) = (@ARGV);
map {shift} 0..3;

while (<>)
{
   map {push @{$s{"$pS,$pJ,$pN"}},"$sS,$sJ,$sN"} {($sS,$sJ,$sN,$pJ,$pS,$pN) = (/DEFINE JOBPRED ID=.(\S+),(\S+),(\d+). PJOB=(\S+) PSET=(\S+) PJNO=(\S+).*/)}
}

Code II
Code:
sub p
{
   if ($d >= $D) {return}

   printf "%3s"x$d++," ";
   printf "%s%s\n",$_[0],$h{$_[0]}?" ** ":"";

   if (!$h{$_[0]})
   {
      $h{$_[0]}=1;
      map {p($_)} @{$s{$_[0]}}
   }
   $d--
}

($Set,$Job,$Num,$D) = (@ARGV);
map {shift} 0..3;

while (<>)
{
   map {push @{$s{"$sS,$sJ,$sN"}},"$pS,$pJ,$pN"} {($sS,$sJ,$sN,$pJ,$pS,$pN) = (/DEFINE JOBPRED ID=.(\S+),(\S+),(\d+). PJOB=(\S+) PSET=(\S+) PJNO=(\S+).*/)}
}

p("$Set,$Job,$Num");

I need to convert this to UNIX Shell (perhaps using awk/sed ?). Could you please advise.

I hope there is sufficient information here.
 

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LEARN ABOUT PHP

cubrid_num_cols

CUBRID_NUM_COLS(3)							 1							CUBRID_NUM_COLS(3)

cubrid_num_cols - Return the number of columns in the result set

SYNOPSIS

       int cubrid_num_cols (resource  $result)

DESCRIPTION

	The cubrid_num_cols(3) function is used to get the number of columns from the query result. It can only be used when the query executed is
       a select statement.

PARAMETERS

	      o $result
		-Result.

RETURN VALUES

	Number of columns, when process is successful.

       FALSE, if SQL statement is not SELECT.

EXAMPLES

       Example #1

	      cubrid_num_cols(3) example

	      <?php
	      $conn = cubrid_connect("localhost", 33000, "demodb", "dba");

	      $req = cubrid_execute($conn, "SELECT * FROM code");

	      $row_num = cubrid_num_rows($req);
	      $col_num = cubrid_num_cols($req);

	      printf("Row Num: %d
Column Num: %d
", $row_num, $col_num);

	      cubrid_disconnect($conn);
	      ?>

	      The above example will output:

	      Row Num: 6
	      Column Num: 2

SEE ALSO

       cubrid_execute(3), cubrid_num_rows(3).

PHP Documentation Group 													CUBRID_NUM_COLS(3)
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