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Top Forums Shell Programming and Scripting Array reference - bad substitution Post 302291851 by swankgd on Thursday 26th of February 2009 12:34:00 PM
Old 02-26-2009
Array reference - bad substitution

I've created a series of arrays named as follows:

row1[]
row2[]
row3[]
.
.
.
row10[]

Each has 4 elements.

I'm trying to echo the array elements out in a for loop. Here's what I have:
Code:
for ((i=1;i<=10;i++))
do
  for ((j=1;j<=4;j++)) 
  do
    eval out=${row`echo $i`[$j]}
    echo -n $out
  done
  echo
done

I get the bad substitution error on the eval out= assignment. Oddly, just a few lines before that, almost the exact same syntax works fine for assigning the values to the arrays ( eval row`echo $i`[$j]=......)

Any help is much appreciated.
 

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ARRAY_REPLACE_RECURSIVE(3)						 1						ARRAY_REPLACE_RECURSIVE(3)

array_replace_recursive - Replaces elements from passed arrays into the first array recursively

SYNOPSIS
array array_replace_recursive (array $array1, array $array2, [array $...]) DESCRIPTION
array_replace_recursive(3) replaces the values of $array1 with the same values from all the following arrays. If a key from the first array exists in the second array, its value will be replaced by the value from the second array. If the key exists in the second array, and not the first, it will be created in the first array. If a key only exists in the first array, it will be left as is. If several arrays are passed for replacement, they will be processed in order, the later array overwriting the previous values. array_replace_recursive(3) is recursive : it will recurse into arrays and apply the same process to the inner value. When the value in $array1 is scalar, it will be replaced by the value in $array2, may it be scalar or array. When the value in $array1 and $array2 are both arrays, array_replace_recursive(3) will replace their respective value recursively. PARAMETERS
o $array1 - The array in which elements are replaced. o $array2 - The array from which elements will be extracted. o $... - Optional. More arrays from which elements will be extracted. RETURN VALUES
Returns an array, or NULL if an error occurs. EXAMPLES
Example #1 array_replace_recursive(3) example <?php $base = array('citrus' => array( "orange") , 'berries' => array("blackberry", "raspberry"), ); $replacements = array('citrus' => array('pineapple'), 'berries' => array('blueberry')); $basket = array_replace_recursive($base, $replacements); print_r($basket); $basket = array_replace($base, $replacements); print_r($basket); ?> The above example will output: Array ( [citrus] => Array ( [0] => pineapple ) [berries] => Array ( [0] => blueberry [1] => raspberry ) ) Array ( [citrus] => Array ( [0] => pineapple ) [berries] => Array ( [0] => blueberry ) ) Example #2 array_replace_recursive(3) and recursive behavior <?php $base = array('citrus' => array("orange") , 'berries' => array("blackberry", "raspberry"), 'others' => 'banana' ); $replacements = array('citrus' => 'pineapple', 'berries' => array('blueberry'), 'others' => array('litchis')); $replacements2 = array('citrus' => array('pineapple'), 'berries' => array('blueberry'), 'others' => 'litchis'); $basket = array_replace_recursive($base, $replacements, $replacements2); print_r($basket); ?> The above example will output: Array ( [citrus] => Array ( [0] => pineapple ) [berries] => Array ( [0] => blueberry [1] => raspberry ) [others] => litchis ) SEE ALSO
array_replace(3), array_merge_recursive(3). PHP Documentation Group ARRAY_REPLACE_RECURSIVE(3)
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