I'm trying to echo the array elements out in a for loop. Here's what I have:
I get the bad substitution error on the eval out= assignment. Oddly, just a few lines before that, almost the exact same syntax works fine for assigning the values to the arrays ( eval row`echo $i`[$j]=......)
Need Help... I am getting a bad substitution error on my script on a Solaris Server. However the script has been proven to work on HPUX and Solaris servers...
#!/usr/bin/sh
#
# Set the location of the tzupdater.jar file
#
JAR=/tmp/tzupdater.jar # <<<<< UPDATE THIS LINE... (3 Replies)
I can't seem to make what appears to be a simple substitution.
I want to define a list of systems for which daily reports need to be filed
systems="systemA systemC systemZ"
I then want to run a loop
for i in ${systems}
Analyze statistics
Create the reports
mailx (8 Replies)
hi,
i created a shell script having the following content:
#! /usr/bin/ksh
FROM="myemail@domain.com"
MAILTO="someemail@domain"
SUBJECT="TEST"
BODY="/export/home/adshocker/body.txt"
ATTACH="/export/home/adshocker/attach.prog"
echo $ATTACH
ATTACH_NAME="${ATTACH##*/}"
echo $ATTACH_NAME... (5 Replies)
#!/bin/bash
a1=( win 12,01,02,03,04 )
a2=( pre 04,05,06 )
a3=( msn 06,07,08,09 )
Given the above arrays, I want the script to return/echo the following in a loop;
win
12,01,02,03,04
pre
04,05,06,07
msn
06,07,08,09
But I can't get it to do as such.
I've tried; (2 Replies)
Hi All,
I'm building a new shell script but i'm facing a problem with one line which is giving "bad substitution" error. Please assist
script lines:
#!/bin/sh
printf "%s: " "Occurrence DATE (YYYYMMDD)"; read DATE
shortdate=${DATE#??}
o/p:
./test1: bad substitution
This command is... (2 Replies)
Hi,
I have a make file which I try to execute, but it failed when it arrived to the line:
for r in ${PIPESTATUS
}; do if (($r != 0)); then exit $r; fi;done;
With the Error:
""make:/bin/sh: Bad substitution""
Or the Error:
"make:${PIPESTATUS[...}: Bad substitution"
(Depend on the operating... (3 Replies)
Why I get bad replace when using eval?
$ map0=( "0" "0000" "0")
$ i=0
$ eval echo \${map$i}
0000
$ a=`eval echo \${map$i}` !!!error happens!!!
bash: ${map$i}: bad substitution
How to resolve it ?
Thanks! (5 Replies)
Cant undestand :) why i have an error on line 2.it is working on my other boxes
#!/bin/bash
ret=$(echo Q | timeout 5 openssl s_client connect "${1`hostname`}:${2-443}" -ssl3 2> /dev/null)
if echo "${ret}" | grep -q 'Protocol.*SSLv3'; then
if echo "${ret}" | grep -q 'Cipher.*0000'; then
... (7 Replies)
i am trying to prepare a train and test dataset, for which i need to randomly split the data into corresponding folders (train,test)..
I began on a simple script, but seem to get som weird error messages, that i cannot make sense of?..
what am I doing wrong?
#!/bin/bash
RED='\033]
then... (13 Replies)
ShellCheck doesn't find any issues with this script.
#!/bin/bash
# color_meanings: explain meanings of colors used in bash ls
eval "$(echo "no:fi:di:ln:pi:so:do:bd:cd:or:mi:su:sg:tw:st:ex" | sed -e 's/:/=/g; s/\;/\n/g')"
{
IFS=:
for i in $LS_COLORS
do
... (18 Replies)
Discussion started by: Xubuntu56
18 Replies
LEARN ABOUT PHP
array_replace_recursive
ARRAY_REPLACE_RECURSIVE(3) 1 ARRAY_REPLACE_RECURSIVE(3)array_replace_recursive - Replaces elements from passed arrays into the first array recursivelySYNOPSIS
array array_replace_recursive (array $array1, array $array2, [array $...])
DESCRIPTION array_replace_recursive(3) replaces the values of $array1 with the same values from all the following arrays. If a key from the first array
exists in the second array, its value will be replaced by the value from the second array. If the key exists in the second array, and not
the first, it will be created in the first array. If a key only exists in the first array, it will be left as is. If several arrays are
passed for replacement, they will be processed in order, the later array overwriting the previous values.
array_replace_recursive(3) is recursive : it will recurse into arrays and apply the same process to the inner value.
When the value in $array1 is scalar, it will be replaced by the value in $array2, may it be scalar or array. When the value in $array1 and
$array2 are both arrays, array_replace_recursive(3) will replace their respective value recursively.
PARAMETERS
o $array1
- The array in which elements are replaced.
o $array2
- The array from which elements will be extracted.
o $...
- Optional. More arrays from which elements will be extracted.
RETURN VALUES
Returns an array, or NULL if an error occurs.
EXAMPLES
Example #1
array_replace_recursive(3) example
<?php
$base = array('citrus' => array( "orange") , 'berries' => array("blackberry", "raspberry"), );
$replacements = array('citrus' => array('pineapple'), 'berries' => array('blueberry'));
$basket = array_replace_recursive($base, $replacements);
print_r($basket);
$basket = array_replace($base, $replacements);
print_r($basket);
?>
The above example will output:
Array
(
[citrus] => Array
(
[0] => pineapple
)
[berries] => Array
(
[0] => blueberry
[1] => raspberry
)
)
Array
(
[citrus] => Array
(
[0] => pineapple
)
[berries] => Array
(
[0] => blueberry
)
)
Example #2
array_replace_recursive(3) and recursive behavior
<?php
$base = array('citrus' => array("orange") , 'berries' => array("blackberry", "raspberry"), 'others' => 'banana' );
$replacements = array('citrus' => 'pineapple', 'berries' => array('blueberry'), 'others' => array('litchis'));
$replacements2 = array('citrus' => array('pineapple'), 'berries' => array('blueberry'), 'others' => 'litchis');
$basket = array_replace_recursive($base, $replacements, $replacements2);
print_r($basket);
?>
The above example will output:
Array
(
[citrus] => Array
(
[0] => pineapple
)
[berries] => Array
(
[0] => blueberry
[1] => raspberry
)
[others] => litchis
)
SEE ALSO array_replace(3), array_merge_recursive(3).
PHP Documentation Group ARRAY_REPLACE_RECURSIVE(3)