See the two values main takes? They contain your commandline arguments. argv is an array of strings containing the arguments, and argc tells you how many strings it has in it. In nearly all cases, the first argument is the name the program was run with, and all the ones after it are the ones you want.
Were you to run your program with my_c_program a b c d, then the contents of argv[] would be { "my_c_program", "a", "b", "c", "d", NULL}, and the value of argc would be 5.
So, run the program like
and that string will be found in argv[1].
Hi,
I have two shell variables $t1 and $t2 which I need to pass to a function in a shell script. The function will do some computation with those two variables and echo the resultant. But I do not know how to pass teh arguments.
The function written is
f1()
{......
........
}
What should... (3 Replies)
I want to pass an array in my function, And my function will be changing the elements of the array in the fuction, but it should not affect the values in my array variable of main function (1 Reply)
Hi
I need to pass an array to Awk script from Shell. Can you please tell how to do it? How to pass this array add_ct_arr to an awk script or access it in awk?
i=1
while ;
do
add_ct_arr=$(echo ${adda_count} | awk -v i=$i -F" " '{print $i;}')
echo ${add_ct_arr}
... (1 Reply)
hi,
I have a array say
SAP_ARRAY="s1.txt"
SAP_ARRAY="s2.txt"
how can i pass this full array to a function.
here is the sample code i am using..
CHECK_NO_FILES()
{
FARRAY=$1
echo "FARRAY = $FARRAY"
echo "FARRAY = $FARRAY"
............... (5 Replies)
Hi, guys
I just wanted to sort the elements of an array ascendingly.
I know the following code does work well:
array=(13 435 8 23 100)
for i in {0..4}
do
j=$((i+1))
while ]
do
if } -le ${array} ]]
then :
else
min=${array}
${array}=${array}
${array}=$min
fi... (5 Replies)
How do i pass an array from test4.sh to a function in another shell script test5.sh, basically i am sourcing the test5.sh in test4.sh and printing the contents, but not working below are my trial scripts, please help, thank you.
#!/bin/bash
# /usr/local/dw/archive/test5.sh
print_array()
{... (5 Replies)
There are two parts to this. In the first part I need to read a list of files from a directory and split it into 4 arrays. I have done that with the following code,
# collect list of file names
STATS_INPUT_FILENAMES=($(ls './'$SET'/'$FOLD'/'*'in.txt'))
# get number of files... (8 Replies)
Hi All
I have multiple arrays like below.
set -A val1 1 2 4 5
set -A val2 a b c d
.
.
.
Now i would like to pass the individual arrays one by one to a function and display/ do some action.
Note : I am using ksh
Can you please advise any solution...
Thanks in advance. (7 Replies)
Dear Friends,
Please help me on this
my script name is send.csh
In this i have written the statement like this
set args = ( city state country price )
I want to pass this array to another c shell called receiver.csh. and i want to use it in this c shell
or
how to pass to... (2 Replies)
I'm able to read & print an array in varaible called "filelist"
I need to pass this array variable to a function called verify() and then read and loop through the passed array inside the function.
Unfortunately it does not print the entire array from inside the funstion's loop.
#/bin/ksh... (5 Replies)
Discussion started by: mohtashims
5 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)