Sponsored Content
Top Forums Shell Programming and Scripting Adding days to an input date. Post 302289821 by hard aix on Friday 20th of February 2009 03:03:21 PM
Old 02-20-2009
Quote:
Originally Posted by sud
isnt working
??

Can you copy/paste and post what happens when you execute those 3 lines of code on your system?
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

adding or subtracting days in the o/p of date

how can we add or subtract days from the output of date command in unix... like if i want to subtract a day from the result of date command like this.. v_date=`date +%Y%m%d` this wud give me 20080519 now i want to subtract one day from this.. so tht it wud give me 20080518.. how do i do... (1 Reply)
Discussion started by: St.Fartatric
1 Replies

2. Shell Programming and Scripting

date for two days or 3 days ago

i need a script that can tell me the date 2 days ago or 3 days ago. please help (7 Replies)
Discussion started by: tomjones
7 Replies

3. Shell Programming and Scripting

how to get what date was 28 days ago of the current system date IN UNIX

Hi, Anybody knows how to get what date was 28 days ago of the current system date through UNIX script. Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Discussion started by: kandi.reddy
15 Replies

4. Shell Programming and Scripting

Date after 5 days from current date in YYYYMMDD format

Hello Experts, How do i get date after 5 days from current date in YYYYMMDD format? How do you compare date in YYYYMMDD format? Thanks (8 Replies)
Discussion started by: needyourhelp10
8 Replies

5. Windows & DOS: Issues & Discussions

Adding or subtracting days from current date in batch script

Hi, I'm writing an batch file to create report In the batch file iam passing two arguments:startdate and finishdate Ex: startdate=07-sep-2009 finishdate=07-sep-2011 I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
Discussion started by: anand1773
2 Replies

6. Shell Programming and Scripting

Number of days between the current date and user defined date

I am trying to find out the number of days between the current date and user defined date. I took reference from here for the date2jd() function. Modified the function according to my requirement. But its not working properly. Original code from here is working fine. #!/bin/sh... (1 Reply)
Discussion started by: hiten.r.chauhan
1 Replies

7. Shell Programming and Scripting

Adding days to system date then compare to a date

Hi! I am trying to read a file and every line has a specific date as one of its fields. I want to take that date and compare it to the date today plus 6 days. while read line do date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD if ; then ...proceed commands ... (1 Reply)
Discussion started by: kokoro
1 Replies

8. Shell Programming and Scripting

UNIX date fuction - how to deduct days from today's date

Hi, One of my Unix scripts needs to look for files coming in on Fridays. This script runs on Mondays. $date +"%y%m%d" will give me today's date. How can I get previous Friday's date.. can I do "today's date minus 3 days" to get Friday's date? If not, then any other way?? Name of the files is... (4 Replies)
Discussion started by: juzz4fun
4 Replies

9. Shell Programming and Scripting

Adding days to date

Hi, please can somebody let me know the easiest way to add days to a date. I can do this in perl but would like to able to do it in a shell script. Desired output would be: date +'%Y-%m-%d' + 10 = 2016-05-02 Thank you (8 Replies)
Discussion started by: andy391791
8 Replies

10. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 11:20 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy