02-17-2009
Hi,
const char *buffer does not mean that buffer is a constant. It only says buffer points to a constant char. To declare buffer as a constant, you will have give,
char * const buffer;
Here in your code, you cannot give
char *b
sprintf(b,"result.txt");
Either you have to allocate memory to b and then use sprintf or strcpy or you can use,
b="result.txt";
To append something to buffer, you dont want to concatinate the new string with buffer, you may append the string to the array buffer points to. You cannot give strcat(buffer,b) as strcat does not allow const char * as its first argument.
You may try this
char b[1024]={"result.txt"}; //You may try dynamic allocation also
const char *buffer=b;
cout<<"\n Value of buffer 1 : "<<buffer<<endl; //It will be result.txt
strcat(b,",result1.txt");
cout<<"\n Value of buffer 2 : "<<buffer<<endl; //It will be result.txt,result1.txt
.
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STRCAT(3) BSD Library Functions Manual STRCAT(3)
NAME
strcat, strncat -- concatenate strings
LIBRARY
Standard C Library (libc, -lc)
SYNOPSIS
#include <string.h>
char *
strcat(char *restrict s1, const char *restrict s2);
char *
strncat(char *restrict s1, const char *restrict s2, size_t n);
DESCRIPTION
The strcat() and strncat() functions append a copy of the null-terminated string s2 to the end of the null-terminated string s1, then add a
terminating '