|
|
Sponsored Content
Top Forums
UNIX for Dummies Questions & Answers
Using GREP to extract variable following a string
Post 302285361 by modey3 on Sunday 8th of February 2009 09:11:33 PM
02-08-2009
|
|
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
I have a variable which consists of a string like this:
001 aaabc 44 a bbb12
How do I extract each substring, delimited by the spaces, into new variables - one for each substring?
eg var1 will be 001, var2 will be aaabc, var3 will be 44, var4 will be a, etc?
I've come up with this:... (2 Replies)
Discussion started by: Sniper Pixie
2 Replies
2. Shell Programming and Scripting
hi,I am new to shell script,I have String,like this:
Number of rows exported: 5321
the numbe at end could changing,how can I extract this number and assign it to a variable,then use it later in script.
thanks. (19 Replies)
Discussion started by: vitesse
19 Replies
3. UNIX for Dummies Questions & Answers
Hello,
I have a question regarding the awk command. Here is the line I need to grep:
1 F= -.13250138E+03 E0= -.13249556E+03 d E =-.174650E-01 mag= 35.2157
Instead of displaying the number in red I would like to store it as a variable such as X. Is there a way to do this? Thanks for any... (3 Replies)
Discussion started by: modey3
3 Replies
4. Shell Programming and Scripting
Hi, guys. I have one question:
I need to search for a string in a file, and then extract another string from the file and assign it to a variable.
For example:
the contents of the file (group) is below:
...
ftp:x:23:
mail:x:34
...
testing:x:2001
sales:x:2002
development:x:2003
...... (6 Replies)
Discussion started by: daikeyang
6 Replies
5. Shell Programming and Scripting
I need to extract certain pieces from a string, wher delimiters may vary. For example
A0 B0 C0 12345677 X0 Y0 Z0
A1-B1 C1 12345678 X1 Y0 Z0
A1/B2 C77 12345679 X2 Y0 Z0
I need to get
C0 12345677 X0
C1 12345678 X1
C77 12345679 X2
I tried sed, see example below:
echo 'A0 B0... (2 Replies)
Discussion started by: migurus
2 Replies
6. Shell Programming and Scripting
I have a file with
<suit:run date="Trump Tue 06/19/2012 11:41 AM EDT" machine="garg-ln" build="19921" level="beta" release="6.1.5" os="Linux">
Need to find word "build" then
extract build number, which is 19921 also
release number, which is 6.1.5 then
concatenate them to one variable as... (6 Replies)
Discussion started by: garg
6 Replies
7. Shell Programming and Scripting
Hi,
I've a file ImageSizeDetails.txt with the following contents:
Image Name: swncd 01.10.00.04
Created: Wed Jan 9 14:05:48 2013
Image Type: ARM Linux Multi-File Image (gzip compressed)
Data Size: 7351011 Bytes = 7178.72 kB = 7.01 MB
Load Address: 00008000
Entry Point: ... (6 Replies)
Discussion started by: Parameswaran
6 Replies
8. UNIX for Dummies Questions & Answers
Hi,
I'm doing a script to list all scripts called by a "master" script.
But I have an issue as there is some variables in the name of the called scripts.
Example:
% cat master_script.sh
ENVIR=PROD
VERSION=1.2
/users/maturix/$ENVIR/program_$VERSION.shI would like my script displays a kind... (7 Replies)
Discussion started by: maturix
7 Replies
9. UNIX for Beginners Questions & Answers
Dear all,
I have a file a.txt like below:
1_234560_A_G_b37 1 2 1 2 2 2 ...
1_35465767_C_T_b37 2 1 1 2 2 2 ...
2_490638010_A_T_b37 1 2 1 2 2 2 ...
10_4567899_T_G_b37 2 2 1 2 2 2 ...
...
what I want to do is extracting rows starting with "10_" like : 10_4567899_T_G_b37 2 2 1 2 2... (1 Reply)
Discussion started by: forevertl
1 Replies
10. UNIX for Beginners Questions & Answers
For example: I am grepping "Hello" from a file and there are 10 matches. So all ten lines with match will get stored into a variable($match). Now I want to ignore those lines which have "Hi" present in that.
Currently I tried this: match = grep "Hello" file | grep -v "Hi" file
But that's not... (2 Replies)
Discussion started by: pavan
2 Replies
LEARN ABOUT DEBIAN
paps
PAPS(1) General Commands Manual PAPS(1) NAME
paps - UTF-8 to PostScript converter using Pango SYNOPSIS
paps [options] files... DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves through the pango ft2 backend. OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is included below. --landscape Landscape output. Default is portrait. --columns=cl Number of columns output. Default is 1. Please notice this option isn't related to the terminal length as in a "80 culums terminal". --font=desc Set the font description. Default is Monospace 12. --rtl Do right to left (RTL) layout. --paper ps Choose paper size. Known paper sizes are legal, letter and A4. Default is A4. Postscript points Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch. --bottom-margin=bm Set bottom margin. Default is 36 postscript points. --top-margin=tm Set top margin. Default is 36 postscript points. --left-margin=lm Set left margin. Default is 36 postscript points. --right-margin=rm Set right margin. Default is 36 postscript points. --gutter-width=gw Set gutter width. Default is 40 postscript points. --help Show summary of options. --header Draw page header for each page. --markup Interpret the text as pango markup. --lpi Set the lines per inch. This determines the line spacing. --cpi Set the characters per inch. This is an alternative method of specifying the font size. --stretch-chars Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops behaviour. AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>. This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others). April 17, 2006 PAPS(1)