given a string passed to a program that supposed to be numeric and of a certain length say 8 digits - so say for e.g. need to verify this 01234567
How would I parse this string to validat it meet requirements
I tried to use * | sed /\(\{8})/
Thanks in advance (1 Reply)
Hello,
I really would appreciate some help with a bash script for some string manipulation on an SQL dump:
I'd like to be able to rename "sites/WHATEVER/files" to "sites/SOMETHINGELSE/files" within the sql dump.
This is quite easy with sed:
sed -e... (1 Reply)
Hi all,
I am trying to find the best way of making a change to 1 char in a string, the string can be between 1 and 14 characters.
I am reading a line in from a file which contains
012341231231:2:102939283:NNN: Require :NBN:
012838238232:3:372932:NNN: Require :NNB:
I need to change 1 N or a... (8 Replies)
Can someone tell me how to change the first column in a very large 17k line file from a random 10 digit numeric value to a non numeric value. The format of lines in the file is:
1702938475,SNU022,201004
the first 10 numbers always begin with 170 (6 Replies)
Hi guys
I am having this strange issue.Well my requirement is like below
Compare two values between flat file and oracle DB
Via perl script I am easily getting the rowcount
Now I connect sql plus via perl and the column value that returns is string
my $sqlplus_settings = '';
my... (7 Replies)
I have a string like
Months=jan feb mar april x y ..
Here the number of fields in Months is not definite
I need to extract each field in the Months string and pass it to awk . Don't want to use for in since it is a loop . How can i do it (2 Replies)
Hello,
I've a file file_1.txt
ul.ln = 'Kb' AND (il.sum = 'ec7ccc92585adac28d9b1fb5eff0473f' or length('ec7ccc92585adac28d9b1fb5eff0473f') = 7);
il.sum = '20ddc1368d588dd0b0e37c41721e05b1' OR length('20ddc1368d588dd0b0e37c41721e05b1') = 7);
I need to replace the file like below -
ul.ln... (4 Replies)
My sample file is variable length, with out any field delimiters. It has min of 18 chars length and the 'CRLF' is potentially between 12-14 chars. How do I replace this with a space? I still want to keep end of record, but just want to remove these new lines chars in the middle of the data.
... (7 Replies)
Discussion started by: chandrath
7 Replies
LEARN ABOUT NETBSD
openssl_passwd
PASSWD(1) OpenSSL PASSWD(1)NAME
passwd - compute password hashes
LIBRARY
libcrypto, -lcrypto
SYNOPSIS
openssl passwd [-crypt] [-1] [-apr1] [-salt string] [-in file] [-stdin] [-noverify] [-quiet] [-table] {password}
DESCRIPTION
The passwd command computes the hash of a password typed at run-time or the hash of each password in a list. The password list is taken
from the named file for option -in file, from stdin for option -stdin, or from the command line, or from the terminal otherwise. The Unix
standard algorithm crypt and the MD5-based BSD password algorithm 1 and its Apache variant apr1 are available.
OPTIONS -crypt
Use the crypt algorithm (default).
-1 Use the MD5 based BSD password algorithm 1.
-apr1
Use the apr1 algorithm (Apache variant of the BSD algorithm).
-salt string
Use the specified salt. When reading a password from the terminal, this implies -noverify.
-in file
Read passwords from file.
-stdin
Read passwords from stdin.
-noverify
Don't verify when reading a password from the terminal.
-quiet
Don't output warnings when passwords given at the command line are truncated.
-table
In the output list, prepend the cleartext password and a TAB character to each password hash.
EXAMPLES
openssl passwd -crypt -salt xx password prints xxj31ZMTZzkVA.
openssl passwd -1 -salt xxxxxxxx password prints $1$xxxxxxxx$UYCIxa628.9qXjpQCjM4a..
openssl passwd -apr1 -salt xxxxxxxx password prints $apr1$xxxxxxxx$dxHfLAsjHkDRmG83UXe8K0.
1.0.1i 2009-07-20 PASSWD(1)