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Top Forums UNIX for Dummies Questions & Answers Execute "find . -exec grep" in desending Order Post 302284798 by gav_dhiman on Friday 6th of February 2009 10:41:39 AM
Old 02-06-2009
Execute "find . -exec grep" in desending Order

Hi Xperts,

I've one query for you. Please help me solving this.

Below command is taking long time to fetch names of the files which contain string "475193976" because folder contains millions of files. I agree that this is what this function suppose to do. Correct.. But can it be possible that this find runs descendingly instead of running ascendingly?

find . -exec grep -l '475193976' {} \;

Lets suppose i've a folder which contain 10 files. Name of these files are below:
date format is (YYYMMDD-HHMMSS)
1st file name = 20080406-011603-132_ICH830_20090206-011519_471
2 = 20080506-011603-132_ICH830_20090206-011519_471
3 = 20080606-011603-132_ICH830_20090206-011519_471
4 = 20080706-011603-132_ICH830_20090206-011519_471
5 = 20080806-011603-132_ICH830_20090206-011519_471
6 = 20081006-011603-132_ICH830_20090206-011519_471
7 = 20081106-011603-132_ICH830_20090206-011519_471
8 = 20081206-011603-132_ICH830_20090206-011519_471
9 = 20090106-011603-132_ICH830_20090206-011519_471
10 = 20090206-011603-132_ICH830_20090206-011519_471

Now if i use the above command "find . -exec grep -l '475193976' {} \;", this will start searchin files from 1 to 10..

My problem is :- Can it run backwards??. i.e 10 to 1. By this way i can get the latest modified file and as soon as i get that file i can cancel the nxt search because my Motive is to find the Latest timestamp file which is "20090206-011603-132_ICH830_20090206-011519_471" in above example. Also there are total of more than 1 lakhs files in folder where we're using find function.

I'll be very thankful If someone can help me in this. ALso i feel i explain the problem is simple and detailed manner just because i can get a good result from you people.

Waiting for your response.

Thanks in Advance.
 

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