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Full Discussion: putting grep -c results number in a variable
Top Forums UNIX for Dummies Questions & Answers putting grep -c results number in a variable Post 302284111 by busdude on Wednesday 4th of February 2009 09:23:47 PM
Old 02-04-2009
putting grep -c results number in a variable
I want to display "no results found" if a grep search of a name that the user inputs is not found anywhere in a certain file,

Right now I have this, but doesn't seem to work. Im not sure what to change.


Code:
read name
 
results=grep -c $name file
if [ $results = 0 ];
then echo "No results found."
exit
else...

 

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LEARN ABOUT BSD

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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