Hi ,
I am relatively new to unix...
Can u pls help me out to find out if the first day of the month is a working day ie from (Monday to Friday)...using Date and If clause in Korn shell..
This is very urgent.
Thanks for ur help... (7 Replies)
How to find the first day of previous month in unix mmddyyyy format?
example : today is 07052007 (in mmddyyyy)
output sud be 06012007
thanks
mohapatra (10 Replies)
Hi,
I want a script(ksh) to see if today is the last working day(Mon-Fri) of the month. If it is the last working day I need to print current date, else I need the last working day of previous month. Thanks in advance. (1 Reply)
Hello,
I wanted to display the month for previous day date. Like, today date is 18-Nov-2008. So the previous date is 17-Nov-2008. The output should be November.
If the today date is 1-DEC-2008, then output should be NOVEMBER.
If the today date is 1-JAN-2008, then output should be DECEMBER.... (4 Replies)
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
I am using the code below modified from a post I saw here regarding having the script write out future dates. The problem is that instead of making 8/1 it makes 7/32! Please help!
yy=`date +%Y`
mm=`date +%m`
dd=`date +%d`
echo "Today is : $yy $mm $dd"
#!/usr/bin/ksh
date '+%m... (5 Replies)
Hello All,
I am trying to come up with a shell script to count a specific word in a logfile on each day of this month, last month and the month before. I need to produce this report and email it to customer.
Any ideas would be appreciated! (5 Replies)
Hi Guys,
How to get First day of previous month and last day of previous month from trunc(sysdate) using SQL..?
Thanks in advance.
Br,
pinpe (2 Replies)
Hi All,
I have a requirement where I need to first capture the current day & move all the files from a particular directory based on a previous day.
i.e move all the files from one directory to another based on current day & a previous day. Here is what I am trying, but it gives me errors.... (2 Replies)
Discussion started by: dsfreddie
2 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)