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Full Discussion: End of Month - Cron Jobs
Top Forums Shell Programming and Scripting End of Month - Cron Jobs Post 302281338 by cfajohnson on Wednesday 28th of January 2009 04:48:12 PM
Old 01-28-2009
Quote:
Originally Posted by jthompson333
I am running AIX 5.3 with the default shell as ksh.

I would like to know how to run a cron job on this system the last calendar day of the month. I found an example, but, I'm not sure if it will work with AIX and ksh...

Code:
02 16 * * * [ $(date +%d) -eq $(echo $(cal) | awk '{print $NF}') ] && /home/user/job-eom.ksh

I also need to be able to run a job on every day except the last calendar of the month (actually a series of jobs, but, I assume I can adopt the syntax for multiple jobs).

So to summarize:

I would like to run the following jobs where specified EXCEPT on the LAST calendar day of the month.

Code:
50   21   *   *   *   /home/user/eod-job1.ksh
00   22   *   *   *   /home/user/eod-job2.ksh
10   22   *   *   0   /home/user/eod-job3.ksh
10   22   *   *   1-4   /home/user/eod-job4.ksh
00   23   *   *   1   /home/user/eod-job5.ksh
10   22   *   *   5-6   /home/user/eod-job6.ksh
50   4    *   *   *   /home/user/eod-job7.ksh

And I would like to run another job ON the LAST calendar day of the month, and probably a couple of others...

Code:
45   20   *   *   *   /home/user/eom-job1.ksh

I'm also fairly new at shell scripting, etc., especially ksh.
Code:
_days_in_month() ## USAGE: days_in_month [month [year]]
{
    case ${1#0} in
        9|4|6|11) _DAYS_IN_MONTH=30 ;; ## 30 days hath September...
        1|3|5|7|8|10|12) _DAYS_IN_MONTH=31 ;;
        2) is_leap_year ${2:-`date +%Y`} && _DAYS_IN_MONTH=29 || _DAYS_IN_MONTH=28 ;;
        *) return 5 ;;
    esac
}

is_leap_year() {
    [ $(( $1 % 4 ))   -eq 0 ] &&
    [ $(( $1 % 100 )) -ne 0 ] ||
    [ $(( $1 % 400 )) -eq 0 ]
}

eval "$( date +"year=%Y month=%m day=%d" )"

_days_in_month "$month" "$year"

if [ $_DAYS_IN_MONTH = ${day#0} ]
then
  : last day of month
else
  : not last day of month
fi

 

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LEARN ABOUT ULTRIX

calendar

calendar(1)						      General Commands Manual						       calendar(1)

Name
       calendar - calendar reminder service

Syntax
       calendar [-]

Description
       The  command  consults the file `calendar' in the current directory and prints out lines that contain today's or tomorrow's date.  The com-
       mand recognizes most month-day dates, such as Dec. 7, december 7, 12/7, but it does not recognize dates formatted in the following ways:  7
       December  or  7/12.  If you give the month as * with a date, such as, * 1, that day in any month will do.  On weekends, specifying tomorrow
       extends through Monday.

       When an argument is present, the command searches through a user's calendar file in his login directory and sends him any positive  results
       by Normally this is done daily under control of

       The  calendar  file  is	first  run  through  the  C  preprocessor, to include any other calendar files specified with the #include syntax.
       Included calendars are shared by all users, and are maintained and documented by the local administration.

Options
       -    Functions for every user who has a calendar file in his login directory.

Restrictions
       The extended idea of tomorrow does not account for holidays.

Files
       calendar
       /usr/lib/calendar to figure out today's and tomorrow's dates
       /etc/passwd
       /tmp/cal*
       /lib/cpp, egrep, sed, mail as subprocesses

See Also
       at(1), cron(8), mail(1)

																       calendar(1)
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