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Full Discussion: unzip command fails in ssh
Top Forums Shell Programming and Scripting unzip command fails in ssh Post 302280098 by cfajohnson on Sunday 25th of January 2009 09:31:39 PM
Old 01-25-2009
Quote:
Originally Posted by farahzaiba
I'm trying to run a set of commands on a remote machine using ssh in a shell script. One of the commands is unzip. But when the execution reaches this command, the script fails with an error that unzip is not found. Below is the code and the error snippet.

Pleae put code inside [code] tags.
Quote:
Code:
sourceDir=$1 ; filename=$3 ; destDir=$2
ssh -l "$remoteuser" "$remotecomputer" "cd ${sourceDir} && cp -rf ${filename} ${destDir} && cd ${destDir} && unzip -o ${filename}" >>
 out

sh: unzip: not found.

I have checked on the remote machine that unzip command exists. I also tried hardcoding the actual file's name as an argument to the unzip, with no luck! The error remains the same.
Any idea why am getting this error?

If it can't find unzip, a path to its argument isn't going to help; try using the full path to unzip.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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