I have a shell script which gets passed a parameter which is a combination of Year and Julian Date <YYYYj>. So April 11th, julian date is 101. So if I wanted April 11th for 2003 I would get the following value 2003101. How would I convert that in unix to be 20030411? I am using the korn shell. (3 Replies)
Hi,
I have script in unix which creates a julian date like 126 or 127
I want convert this julian date into calender date
ex : input 127
output 07/may/2007 or 07/05/2007 or 07/05/07
rgds
srikanth (6 Replies)
Hi Guys.
I am very new to UNIX.
I need to get yesterdays and tommorows date given todays date.
Which command and syntax do i use in basic UNIX shell.
Thanks. (2 Replies)
I'm trying to put together a little script that will move some files to a directory, uncompress the file then delete the file when processing is complete.
The files are all named using julian date
2009072.Z
2009071.Z
2009070.Z
2009069.Z
2009068.Z
2009067.Z
2009066.Z
2009065.Z... (8 Replies)
Hi All,
Can anybody help me to get the yesterdays date in perl script.
My script is as below
#!/bin/perl -w
$yes=system("TZ=IST+24 date +%d-%m-%Y");
print "$yes\n";
script is writting the date but with 0
pls see the output below
#!/bin/perl -w
$yes=system("TZ=IST+24 date... (2 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
This function is given the day, month and year and returns the Julian date. The Julian date is the... (1 Reply)
Hi all,
I require to convert julian date to normal calander date in unix
for eg julian date=122
now i want corresponding calander date
----------------------------------------
gr8 if give very small command/script
and please explain the steps as well(imp)
Thanks
... (3 Replies)
Hi,
I have been trying to get the yesterdays date for the Input date I pass.
I know how to do for the current timestamp but how to do for the input date.
Is there any way I can convert to epoch time and do manipulations and back to human readable date?
Please help
Thanks
... (1 Reply)
Discussion started by: abhi1988sri
1 Replies
LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)