Hi,
I'm quite new to scripting and I want to modify following line of an existing script:
MYVAR=`subst |grep 'L:\\\:' | sed -e 's/.*\\\//'`;
What I have to do is to use the content of a variable instead of the constant expression 'L:\\\:' as the grep string to be matched.
Assuming I already... (5 Replies)
Hi Friends...
Please assist me to assign the result of a SQL query that results two column, to two variables.
Pls find the below code that I write for assigning one column to one variable. and please correct if anything wrong..
#! /bin/sh
no='
sqlplus -s uname/password@DBname... (4 Replies)
Hi friends,
firstly, i can run following expression and i took 100 value.
sqlplus -s username/password@TTTEST @umt.sql
umt.sql exists "select t.deger from parametre t where t.id=30".
result of this query =100
i need to assign this value(100) to variable(for example x... (2 Replies)
Dear All,
we have a command output which looks like :
Total 200 queues in 30000 Kbytes
and we're going to get "200" and "30000" for further process. currently, i'm using :
numA=echo $OUTPUT | awk '{print $2}'
numB=echo $OUTPUT | awk '{print $5}'
my question is : can I use just one... (4 Replies)
Hi
im trying to assign the result of the db2 command to a variable inside a shell script...
: tab_cnt=`db2 "select count(*) from syscat.tables where tabname = 'ABC' and tabschema = 'MATT01'" |head -4|tail +4|cut -c 11`
: echo $tab_cnt
when i echo im getting a blank value.. im expecting... (1 Reply)
Hi,
I have the following command that lists all the .o files from all the directories except of vwin (which I don't want it)
for i in `ls -d */*.o|awk '$0 !~ "vwin"'`; do echo $i; done
The result is something like that
dir1/file1.o
dir1/file2.o
dir2/file3.o
etc.
So, I want to create a... (9 Replies)
Hello,
I have searched but failed to find what exactly im looking for,
I need to eliminate first "." in a output so i can use something like the following
echo "./abc/20141127" | nawk '{gsub("^.","");print}'
what i want is to use gsub result later on, how could i achieve it?
Let say... (4 Replies)
I am reading lines from a file that contain a number sign (#) before a three or four digit number:
#1043
#677
I can remove the '#' and get just the number. However, I then want to assign that number to a variable and use it as part of a path further on in my program:
/mydir/10/1043 for... (5 Replies)
I have the following script, and I want to assign the output ($10 and $5) from awk to N and L:
grdinfo data.grd | awk '{print $10,$5}'| read N L
output from gridinfo data.grd is: data.grd 50 100 41 82 -2796 6944 0.016 0.016 3001 2461. where N and L is suppose to be 3001 and 100. I use... (8 Replies)
Discussion started by: geomarine
8 Replies
LEARN ABOUT PHP
datefmt_set_lenient
DATEFMT_SET_LENIENT(3) 1 DATEFMT_SET_LENIENT(3)IntlDateFormatter::setLenient - Set the leniency of the parser
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::setLenient (bool $lenient)
DESCRIPTION
Procedural style
bool datefmt_set_lenient (IntlDateFormatter $fmt, bool $lenient)
Define if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. Enabling lenient parsing allows
the parser to accept otherwise flawed date or time patterns, parsing as much as possible to obtain a value. Extra space, unrecognized
tokens, or invalid values ("February 30th") are not accepted.
PARAMETERS
o $fmt
- The formatter resource
o $lenient
- Sets whether the parser is lenient or not, default is TRUE (lenient).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
datefmt_set_lenient(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt, false);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : ".intl_get_error_message();
echo "
Error_code is : ".intl_get_error_code();
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
The above example will output:
lenient of the formatter is : TRUE
Trying to do parse('35/13/1971').
Result is : 66038400
Now lenient of the formatter is : FALSE
Trying to do parse('35/13/1971').
Result is :
Error_msg is : Date parsing failed: U_PARSE_ERROR
Error_code is : 9
SEE ALSO datefmt_is_lenient(3), datefmt_create(3).
PHP Documentation Group DATEFMT_SET_LENIENT(3)