Hi all,
I've used various scripts in the past to work out the date last week from the current date, however I now have a need to work out the date 1 week from a given date.
So for example, if I have a date of the 23rd July 2010, I would like a script that can work out that one week back was... (4 Replies)
Hi,
In a field, I should receive the date with time stamp in a particular field. But sometimes the vendor sends just the date or the timestamp or correctl the date×tamp. I have to figure out the the data is a date or time stamp or date×tamp.
If it is date then append "<space>00:00:00"... (1 Reply)
Hi All,
I am trying to convert the date of all files under a directory in seconds,
PFB script
a=`ls -lrt | wc -l`
echo $a
for ((i=1;i<=$a;i++))
do
A=`ls -lrt | awk '{print $6,$7,$8}' | head -$i | tail -1`
echo ${A}
date -d '${A}' +%s
donebut I am getting error
date: invalid date... (1 Reply)
Hi All,
How to validate the 4th column,it is date column in the file, if it valid move to valid file else moved invalid file.
9f680174-cb87|20077337254|0|20120511|N
9f680174-cb88|20077337254|0|20120534|N
i want two file valid.txt and invalid.txt
Thanks, (7 Replies)
Dear all,
I have 2 questions.
I have a file with many rows which has date of the format YYYYMMDD.
1. I need to change the date to that weeks friday date(Ex: 20120716(monday) to 20120720). Satuday/Sunday has to be changed to next week friday date too.
2. After converting the date to... (10 Replies)
I have file listed like below
-rw-r--r--+ 1 test test 17M Nov 26 14:43 test1.gz
-rw-r--r--+ 1 test test 0 Nov 26 14:44 test2.gz
-rw-r--r--+ 1 test test 0 Nov 27 10:41 test3.gz
-rw-r--r--+ 1 test test 244K Nov 27 10:41 test4.gz
-rw-r--r--+ 1 test test 17M Nov 27 10:41 test5.gz
I... (5 Replies)
Hi, I have a function to calculate "yesterday" in format YYYYMMDD:
desa_ev9 # date +"%Y%m%d" --date "-1 day 20180701"
20180630
desa_ev9 # date +"%Y%m%d" --date "-1 day 20180720"
20180719
desa_ev9 # date +"%Y%m%d" --date "-1 day 20190101"
20181231
desa_ev9 # date +"%Y%m%d" --date "-1... (2 Replies)
i try to set linux date & time in specific format but it keep giving me error
Example :
date "+%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01"
or
date +"%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01"
keep giving me this error :
date: invalid date ‘19-01-2017 00:05:01'
Please use CODE tags... (7 Replies)
Can someone help me with the code wherein there is a file f1.txt with different column and 34 column have expiry date and I need to get that and compare with system date and if expiry date is <system date remove those rows and other rows should be moved to new file f2.txt .
I don't want to delete... (2 Replies)
I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
Discussion started by: Stuti
1 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)