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Full Discussion: Moving files
Top Forums Shell Programming and Scripting Moving files Post 302278755 by venkatesht on Wednesday 21st of January 2009 05:08:35 AM
Old 01-21-2009
Moving files

I wrote a script which moves files on first in first out basis.

for i in `ls -ltr | grep ^- | head -10 | awk '{print $9}'`
do
mv $i Test/
done

But donno some reason, this is not working on my Linux box. May i know the reason?

Can the above script be done by using positional parameters?

for i in $*
do
cd $1
x = `ls -ltr | grep ^- | head -10 | awk '{print $9}'`
mv $x $2
done

please correct me.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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