I was hoping to get some assistance with this C program I am working on. The goal is to find the largest file in the current directory and then display this filename along with the filesize. What I have so far will display all the files in the current directory. But, how do I deal with "grabbing"... (1 Reply)
I need to find the largest files in a directory & it's subdirectories.
I'm not sure what options on ls -l will work to give me this. or is there another way to do this?
Thanks,
igidttam (6 Replies)
I'm trying to find the 50 largest file in a directory named /sasdb and its' subdirectories. I'm using the find command and a pipe to awk
Not sure if I'm actually getting the largest files from this directory and its subdirectories. Here is the code I used...
find /sasdb -ls | awk '{print... (8 Replies)
Hi,
1)I have XX directory and have lot of files ,I want to find largest file in that
directory
2)how calculate the size of file in MB.
Thanks,
Mohan (15 Replies)
What is the correct command for finding and displaying the largest file on the system?
I don't know how to specify "largest" with "find", and pipe that to something that will display the file contents. Or should I be using cat, more, less, ls, or something else? (4 Replies)
What is the best way to find the largest files in a directory? I used du -k|sort -rn |less.
I got a results for this. But if I used the following command , I got another result...a different order in the same directory. Why is that?
ls -la |awk '{print $5," ",$9}' sort -rn|less. I saw that... (6 Replies)
Hi Experts,
1. In unix how to list the largest file in given directory.
The answer will in single line statement.
2. I have Sun solaris live CD .I try to compile sample c program using "CC compiler".But its shows "cc command not found".
Please help on this.
Thanks in advance.... (4 Replies)
I would need a command for finding first 15000 of the file names whose 25th postion is 5 in the current directory alone.
I do have this painful command
find . -name '5*' | head -15000 | cut -c3-
please refine this.
Of course the above command also searches in the sub directories... (3 Replies)
Discussion started by: vk39221
3 Replies
LEARN ABOUT DEBIAN
plan9-join
JOIN(1) General Commands Manual JOIN(1)NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If one of the file names is the
standard input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Input fields are normally separated spaces or tabs; output fields by space. In this case, multiple separators count as one, and leading
separators are discarded.
The following options are recognized, with POSIX syntax.
-a n In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-v n Like -a, omitting output for paired lines.
-e s Replace empty output fields by string s.
-1 m
-2 m Join on the mth field of file1 or file2.
-jn m Archaic equivalent for -n m.
-ofields
Each output line comprises the designated fields. The comma-separated field designators are either 0, meaning the join field, or
have the form n.m, where n is a file number and m is a field number. Archaic usage allows separate arguments for field designators.
-tc Use character c as the only separator (tab character) on input and output. Every appearance of c in a line is significant.
EXAMPLES
sort /etc/passwd | join -t: -1 1 -a 1 -e "" - bdays
Add birthdays to the /etc/passwd file, leaving unknown birthdays empty. The layout of /adm/users is given in passwd(5); bdays con-
tains sorted lines like
tr : ' ' </etc/passwd | sort -k 3 3 >temp
join -1 3 -2 3 -o 1.1,2.1 temp temp | awk '$1 < $2'
Print all pairs of users with identical userids.
SOURCE
/src/cmd/join.c
SEE ALSO sort(1), comm(1), awk(1)BUGS
With default field separation, the collating sequence is that of sort -b -ky,y; with -t, the sequence is that of sort -tx -ky,y.
One of the files must be randomly accessible.
JOIN(1)