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Full Discussion: Dealing with log files
Top Forums Shell Programming and Scripting Dealing with log files Post 302278277 by ynilesh on Monday 19th of January 2009 11:01:08 PM
Old 01-20-2009
You can grep for "Jan 17".
Quote:
cat log.file | grep "Jan 17"
 

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LOG1P(3)								 1								  LOG1P(3)

log1p - Returns log(1 + number), computed in a way that is accurate even when the value of number is close to zero

SYNOPSIS
float log1p (float $number) DESCRIPTION
log1p(3) returns log(1 + $number) computed in a way that is accurate even when the value of $number is close to zero. log(3) might only return log(1) in this case due to lack of precision. PARAMETERS
o $number - The argument to process RETURN VALUES
log(1 + $number) CHANGELOG
+--------+--------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+--------------------------------------------------+ | 5.3.0 | | | | | | | This function is now available on all platforms | | | | +--------+--------------------------------------------------+ SEE ALSO
expm1(3), log(3), log10(3). PHP Documentation Group LOG1P(3)
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