One of the many methods is to temporarily adjust the timezone.
This example is for UK. The actual adjustment varies according to normal TZ.
#!/bin/ksh
echo "Yesterday : $(TZ=GMT24BST;date)"
echo "Today : $(date)"
echo "Tomorrow : $(TZ=GMT-24BST;date)"
Hi All,
How to find a date which is 7 days from the current date as well as how to find a date which is 7 days before this current date.
Urgently i need help.
Thanks in Advance
Regards
Arunava (2 Replies)
Hi,
I am trying to modify a script which accepts date in format dd/mm/yy. I am trying to modify the script so that it retrieves the date that was 15 days earlier from today as start date. Eg.if today is 05/09/2006, the script should retrieve 21/08/2006 as start date. Is there any script/code to... (2 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hi All,
I need to run a job every month at the beginning of the month which is scheduled through autosys, lets say on 03/01/2010. I need to pass the last month's i.e February's first_date = 02/01/2010 and last_date = 02/28/2010 as variables to a stored procedure. Can somebody please pass... (2 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
Hi all,
I have a variable where it has a past date value in the format YYYY-MM-DD
eg->
pcontromModate="2008-11-31"
How can i get the date 1 day before the pcontromModate.
The required date is 2008-11-30. ..Plz reply since its an urgent one (2 Replies)
I have requirment to get last date of previous month and the first date of previous 4th month:
Example:
Current date: 20130320 (yyyymmdd)
Last date of previous month: 20130228 (yyyymmdd)
First date of previous 4th month: 20121101 (yyyymmdd)
In my shell --date, -d, -v switches are not... (3 Replies)
Hello:
I am bit puzzled with what I could be doing wrong and any help is appreciated.
I have a date in YYYMMDD format and I need to find the previous date. Based on the input on this forum, I have come up with the following. It seems to work for all except the following. Here I am passing date... (3 Replies)
hi all,
need a script or command to get the previous date for the given input date...
like in my script i will pass date as input parameter like 2014-12-01 and i want the output as previous date.. ie.. 2014-11-30 (2 Replies)
I am not able to fetch first date and last date previous month
date -d -1month +%Y-%m-%d
date -d -1month +%Y-%m-%d
I need two format dd-mm-yyy
previous month 01-03-2016
previous month 31-03-2016
and also only date 1 to 31
Aprriciate your replay (4 Replies)
Discussion started by: jagu
4 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)