I have the following situation
============
export DirectoryName=/tmp/xyz
if ; then
some_new_env=$DirectoryName"/*"
=======================
I tried all the ways of escaping the '*', but still the shell seems to expand the '*' character. I want some_new_env to contain "/tmp/xyz/*"
... (7 Replies)
Hi
just for regular use i m working on small module written in perl for getting date in specified format like i have to specify date format and then seperator to seperate date i am 95% done. now i m sure explanation i gave is not good enough so i am putting output here :
C:\Documents and... (2 Replies)
I want to append the following line to /var/spool/cron/root:
*/7 * * * * /root/'Linux CPU (EDF).sh' > /dev/null 2>&1
How to accomplish this using echo?
---------- Post updated at 04:09 PM ---------- Previous update was at 04:07 PM ----------
"Linux CPU (EDF)" is actually stored in a... (11 Replies)
Hi,
I have pipe delimited file in which some of the description fields can have commas. e.g.
1|123|abc,def
2|456|qwert
3|345|aty,try,rty
I need to convert this to a 'csv' file BUT i need to add \ before every comma present in the description values (so that my next program can read it as... (3 Replies)
Hello
This should be easy, but bash is giving me headaches.
At the command line the following command works:
duplicity --include /home --exclude '**' / file:///foo
Doing that from a script is not straightforward. Note that it is basically a requirement that I place the... (3 Replies)
Hi
I use :
path=/var/www/admin
echo "$path" | sed -e 's/\//\\\//g'
this return
\/var\/www\/admin
and is ok.
but
path2=`echo "$path" | sed -e 's/\//\\\//g'`
echo $path2
return an error:
sed: -e expression #1, char 9: unknown option to `s'
Can anyone help me?
Thanks (3 Replies)
So I understand that I should be able to ouput a literal \ by escaping it with a preceding \. My problem is that I am trying to ouput a script that will subsequently be run on a different system with UNC pathing, so I want to ouput two \\ in a row, but escaping them both in sequential order is not... (4 Replies)
Discussion started by: JourneyRider
4 Replies
LEARN ABOUT LINUX
bashbug
BASHBUG(1) bashbug BASHBUG(1)NAME
bashbug - report a bug in bash
SYNOPSIS
bashbug [--help] [--version] [bug-report-email-addresses]
DESCRIPTION
bashbug is a utility for reporting bugs in Bash to the maintainers.
bashbug will start up your preferred editor with a preformatted bug report template for you to fill in. Save the file and quit the editor
once you have completed the missing fields. bashbug will notify you of any problems with the report and ask for confirmation before
sending it. By default the bug report is mailed to both the GNU developers and the Debian Bash maintainers. The recipients can be changed
by giving a comma separated list of bug-report-email-addresses.
If you invoke bashbug by accident, just quit your editor. You will always be asked for confirmation before a bug report is sent.
OPTIONS --help
Show a brief usage message and exit.
--version
Show the version of bashbug and exit.
bug-report-email-addresses
Comma separated list of recipients' email addresses. By default the report is mailed to both the GNU developers and the Debian Bash
maintainers.
ENVIRONMENT
DEFEDITOR
Editor to use for editing the bug report.
EDITOR
Editor to use for editing the bug report (overridden by DEFEDITOR).
SEE ALSO bash(1), reportbug(1), update-alternatives(8) for preferred editor.
AUTHOR
This manual page was written by Christer Andersson <klamm@comhem.se> for the Debian project (but may be used by others).
GNU Bash 3.1 11 December 2007 BASHBUG(1)