01-12-2009
awk problem when attributing query to a variable
Hello,
I'm trying to make a script which reads the PID of a process using awk. I've read the thread in this forum where it is explained.
However, the problem i'm having is when attributing that PID value to a variable.
I'm using AIX 5.3.
The command is the following:
:/home/user1>ps -ef | grep xellerate | grep -i java | awk '{ print $2 }'
958598
Which as you can see.. works.
The problem i'm having is when I try to execute a script which is the following:
#!/bin/ksh
pid=""
pid='ps -ef && grep xellerate && grep -i java && awk '{print $2}''
echo $pid
:/home/user1> ./watchdog2
./watchdog2[3]: }: not found.
:/home/ias1013> pid='ps -ef && grep xellerate && grep -i java && awk '{print $2}''
/bin/ksh: }: not found.
AWK is not doing what I want it to.
Does anyone have any ideas why?
Thanks in advance,
Mambo
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IGAWK(1) Utility Commands IGAWK(1)
NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO
gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)