That is only a snippet of a script; it cannot be run as is.

Many variables are not initialized.

while [ $j -lt $outer ];do

Neither $j nor $outer is initialized.

b=${ARRAY2[j]}
i=0
while [ $i -lt $count ];do

$count is not initialized.

a=${ARRAY1[k]}
fin[i]=`echo $a - $b | bc`

What are the values of $a and $b? Are they integers? If so, you don't need to call an external command.

echo -e  "${fin[i]}," >> try

Is this what you want:

Code:

printf "%s," "${fin[i]}," >> try

((i++))
((k++))

It's better to use the standard format for arithmetic:

Code:

i=$(( $i + 1 ))
k=$(( $k + 1 ))

done
echo -n >> try
#add statement to format output here
#printf "\t" >> try
#echo -e '\t' >> nik
((j++))

See above.