I want to exclude (-v) blank records from a file before analysing it.
I know I can use '^]$' for spaces and tabs but how do you look for lines that have nothing (/n or line feed) ? (2 Replies)
Wants to print line when there exist leading or trailing space or tab in fields 2,3 and 5
The below code prints all lines in file even if they dont have leading and trailing space or tab.
nawk -F"|" '{for(i=1;i<=NF;i++) {if ($i ~ "^*" || $i ~ "*$")}}1' file
file
Ouput required:
... (5 Replies)
Hello,
Is there a direct command to check if the delimiter in your file is a tab or a space? And how can they be converted from one to another.
Thanks,
G (4 Replies)
Hi, I want to read lines from a file, and I'm using two methods
1 use
while read line
do
done<filename
2 use
line=`sed -n '3p' filename`
however, in both of them, I notice that the tab between fields are automatically converted to space
because I want to use awk over the... (10 Replies)
Hi,
I have a space delimited text file but I only want to change the first space to a tab and keep the rest of the spaces intact. How do I go about doing that? Thanks! (3 Replies)
I have a variable sumOfJEOutputFile which is the output file of an SQL command which contains the output of that SQL. The output looks like below:
-----------
58
I am using following code to manipulate the output:
(sed 1,2d $sumOfJEOutputFile > $newTemp1 | sed '$d' $newTemp1)... (4 Replies)
Input file:
xyz,pqrs.lmno,NA,NA,NA,NA,NA,NA,NA
abcd,pqrs.xyz,NA,NA,NA,NA,NA,NA,NA
Expected Output:
xyz pqrs.lmno NA NA NA NA NA NA NA
abcd pqrs.xyz NA NA NA NA NA NA NA
Command Tried so far:
awk -F"," 'BEGIN{OFS=" ";} {print}' $File_Path/File_Name.csv
Issue:... (5 Replies)
My file looks like
3 33 210.01.10.0 2.1 1211 560 26 45 1298 98763451112 15412323499 INPUT OK
3 233 40.01.10.0 2.1 1451 780 54 99 1876 78787878784 15423210199 CANCEL OK
Aim is to replace the spaces in each line by tab
Used: sed -e 's/ */\t/g'
But I get output like this... (3 Replies)
Discussion started by: sa@@
3 Replies
LEARN ABOUT CENTOS
ssh-ldap-helper
SSH-LDAP-HELPER(8) BSD System Manager's Manual SSH-LDAP-HELPER(8)NAME
ssh-ldap-helper -- sshd helper program for ldap support
SYNOPSIS
ssh-ldap-helper [-devw] [-f file] [-s user]
DESCRIPTION
ssh-ldap-helper is used by sshd(1) to access keys provided by an LDAP. ssh-ldap-helper is disabled by default and can only be enabled in the
sshd configuration file /etc/ssh/sshd_config by setting AuthorizedKeysCommand to ``/usr/libexec/openssh/ssh-ldap-wrapper''.
ssh-ldap-helper is not intended to be invoked by the user, but from sshd(8) via ssh-ldap-wrapper.
The options are as follows:
-d Set the debug mode; ssh-ldap-helper prints all logs to stderr instead of syslog.
-e Implies -w; ssh-ldap-helper halts if it encounters an unknown item in the ldap.conf file.
-f ssh-ldap-helper uses this file as the ldap configuration file instead of /etc/ssh/ldap.conf (default).
-s ssh-ldap-helper prints out the user's keys to stdout and exits.
-v Implies -d; increases verbosity.
-w ssh-ldap-helper writes warnings about unknown items in the ldap.conf configuration file.
SEE ALSO sshd(8), sshd_config(5), ssh-ldap.conf(5),
HISTORY
ssh-ldap-helper first appeared in OpenSSH 5.5 + PKA-LDAP .
AUTHORS
Jan F. Chadima <jchadima@redhat.com>
BSD April 29, 2010 BSD