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Full Discussion: Shift Question (Perl)
Top Forums Shell Programming and Scripting Shift Question (Perl) Post 302274529 by ifeatu on Wednesday 7th of January 2009 09:08:17 PM
Old 01-07-2009
help
Okay I'm getting a syntax error here is my code

Code:
open(FILE, "test2.txt") or die ("The file is not found");

$citymap = ( UC => "Union City", VJ => "Vallejo", Vallejo => "Vallejo", Union Ci
ty => "Union City", berk => "Berkeley", Berk => "Berkeley" );
$month2int  = ( Jan => 1, Feb => 2, Mar => 3, mar => 3, March => 3, Apr => 4, ap
r => 4, April => 4, may => 5, May => 5, Jun => 6, Jul => 7, July => 7, jul => 7,
 aug => 8, Aug => 8, August => 8, august => 8, Sept => 9, September => 9, sept =
> 9,Okt => 10, Oct => 10, October => 10, oct => 10, nov => 11, Nov => 11, Novemb
er => 11, november => 11, Dec => 12, December => 12, december => 12);

while (<FILE>) {
($city,$year,$month,$day,$title,$speaker)=split('-');
$month=exists $month2int{$month} ? $month2int{$month} : $month;
$city=exists $citymap{$city} ? $citymap{$city} : ucfirst($city);
print join("-",$city,$year,$month,$day,$title,$speaker);
}

I run the command:
Code:
perl ConvertingFileNames

and my error is:

Code:
syntax error at ConvertingFileNames line 3, near "Union City"
Execution of ConvertingFileNames aborted due to compilation errors.

I noticed in the code you gave me you had a prefix of "%" instead of "$" for the variables defining the month and Location...I tried running with both and it gives me the same error

So I like to talk my code out in words correct me if I'm wrong here but this is what I have so far:

1. Open the file with the file names
2. Define variables to compare the file to
3. While not eof take each line of the file and split it by "-" and put each split value into a unique variable
4. Check two of the variables (month and location) against the two variables defined before the "while" statement
5. make the appropriate changes or do nothing if nothing matches
6. print each line of the file back in the same order it was found with the appropriate changes
7. Close file

Can you help me with syntax?
 

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LEARN ABOUT REDHAT

cal

CAL(1)							    BSD General Commands Manual 						    CAL(1)

NAME

     cal -- displays a calendar

SYNOPSIS

     cal [-smjy13] [[month] year]

DESCRIPTION

     Cal displays a simple calendar.  If arguments are not specified, the current month is displayed.  The options are as follows:

     -1      Display single month output.  (This is the default.)

     -3      Display prev/current/next month output.

     -s      Display Sunday as the first day of the week.  (This is the default.)

     -m      Display Monday as the first day of the week.

     -j      Display Julian dates (days one-based, numbered from January 1).

     -y      Display a calendar for the current year.

     A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
     dar for 1989.  Two parameters denote the month (1 - 12) and year.	If no parameters are specified, the current month's calendar is displayed.

     A year starts on Jan 1.

     The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September.  By this time, most countries had recognized the ref-
     ormation (although a few did not recognize it until the early 1900's.)  Ten days following that date were eliminated by the reformation, so
     the calendar for that month is a bit unusual.

HISTORY

     A cal command appeared in Version 6 AT&T UNIX.

OTHER VERSIONS

     Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
     For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.

BSD
								   June 6, 1993 							       BSD
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