Hi I'm new to this. I need to cut off the last 10 digits from a line.
I've used awk {'print $4'} filename.txt | cut -c 32-42 but this does not guarantee only the last 10 characters.
Please help. Thanks.
Sara (4 Replies)
Hi All,
I am new to shell script.
I wrote a very small script that takes only digits as input-
but there is some problem in that.can you help me in debugging that.
#!/bin/ksh
echo "Digits as input"
read number
digit='eval '
if ]
then
echo "Entered number is a digit"
else
echo... (2 Replies)
hi group,
How can I count total number of 5's which are continuous in the end. i.e. in the below string, the o/p should be 4
I just know to calculate total number of 5's
$ echo "95952325555" | awk -F "5" '{print NF-1}'
6 (3 Replies)
Hi Folks
Probably an easy one here but how do I get a sequence to get used as mentioned. For example in the following I want to automatically create files that have a 2 digit number at the end of their names:
m@pyhead:~$ for x in $(seq 00 10); do touch file_$x; done
m@pyhead:~$ ls file*... (2 Replies)
Hello all! I've looked all over the internet and this site and have come up a loss with an easy way to make a bash script to do what I want to do. I have a file with a naming convention as follows:
2012-01-18 string of words here 123.jpg
2012-01-18 string of words here 1234.jpg
2012-01-18... (2 Replies)
Hi experts,
I have two values in the file :
For example :
partcamt = 72.90
partdamt=27.9
I need to convert these values into 6 digits and ignore the "." sign so that the desired desired output is :
total value= 0072000027900
Currently I am using the following code :
... (3 Replies)
Hi,
How I can replace last 8 ZEROS with 22991231?
19523479811841494432A2013052700000000
19523479811730333980A2013052700000000
19523479811417044397A2013052700000000
19523479811205895810C2013010120130131
A9523479811205895810A2013020120130228
19523479811205895810I2013030120130331... (9 Replies)
Is there any program that can create 6 digit numbers with:
(DIGIT_1)+(DIGIT_2)+(DIGIT_3)+(DIGIT_4)+(DIGIT_5)+(DIGIT_6)=10
Any perl or C also can. Anyone can help me? Thank you (6 Replies)
Hello everybody
I'm a little beginer for shell script as I started last night...
I have this script
cat fichier.txt | while read l ; do
#echo $l
echo $x
x=$(( $x + 1 ))
done
it's return
1
2
3
4 (4 Replies)
Hi All ,
I am having an input file as stated below
5728 U_TOP_LOGIC/U_CM0P/core/u_cortexm0plus/u_top/u_sys/u_core/r03_q_reg_20_/Q 011
611 U_TOP_LOGIC/U_CM0P/core/u_cortexm0plus/u_top/u_sys/u_core/r04_q_reg_20_/Q 011
3486... (4 Replies)
Discussion started by: kshitij
4 Replies
LEARN ABOUT MOJAVE
echo
ECHO(1) BSD General Commands Manual ECHO(1)NAME
echo -- write arguments to the standard output
SYNOPSIS
echo [-n] [string ...]
DESCRIPTION
The echo utility writes any specified operands, separated by single blank (' ') characters and followed by a newline ('
') character, to the
standard output.
The following option is available:
-n Do not print the trailing newline character. This may also be achieved by appending 'c' to the end of the string, as is done by iBCS2
compatible systems. Note that this option as well as the effect of 'c' are implementation-defined in IEEE Std 1003.1-2001
(``POSIX.1'') as amended by Cor. 1-2002. Applications aiming for maximum portability are strongly encouraged to use printf(1) to sup-
press the newline character.
Some shells may provide a builtin echo command which is similar or identical to this utility. Most notably, the builtin echo in sh(1) does
not accept the -n option. Consult the builtin(1) manual page.
EXIT STATUS
The echo utility exits 0 on success, and >0 if an error occurs.
SEE ALSO builtin(1), csh(1), printf(1), sh(1)STANDARDS
The echo utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'') as amended by Cor. 1-2002.
BSD April 12, 2003 BSD