I have a variable which should be any number between 1 and 50.
It could also be any string/empty string.
I have a code written below. The point is when the variable contains string.
I don't want the code below to error out. Instead fall in the else bucket.
You don't have an "else bucket"; dothis_2 will be executed if either the numerical test or dothis_1 fails.
How can I test a variable to see if its in the right format?
The format for the variable would be 'DDMMYYYY HH:MM:SS' and is passed from a command line argument.
Any help would be appreciated (2 Replies)
hi forum
i beginning with script and i want test un null variable in a schell
i just don t know the syntax here is a litle example
y=test
echo $y
unset y
echo $y (so here Y = Null)
if Y=Null
then
echo "y is null"
exit
fi (1 Reply)
I'm using the following line in bash to test whether an argument supplied is an absolute path or not:
if echo $1 | grep '^/' > /dev/null
then
absolute=1
else
absoute=0
fi
The line appears to work but seems somewhat unprofessional looking to me. Is it an acceptable... (2 Replies)
hi,
i store a constant in a variable and want to test whether it is M or Z.
how can i achieve this?? please help
variable='M'
if
then
ehco 'success'
fi;
is this right ?? (2 Replies)
I'm trying to test and see whether a variable that is being extracted from a line in a file is numeric or not. I have tried everything that I can think of and I cannot figure out how to get it to work. I am trying to test and see if the string extracted contains 5 numeric digits. This is what I... (8 Replies)
This is the code:
while test 1 -eq 1
do
read a
$a
if test $a = stop
then
break
fi
done
I read a command on every loop an execute it.
I check if the string equals the word stop to end the loop,but it say that I gave too many arguments to test.
For example echo hello.
Now the... (1 Reply)
Hello, Unix-forums!
My problem:
read -p "Enter any number, please" number
sleep 1
echo $number | tr -d 0-9
test -z $number && echo "Thank you" || echo "This is not a number"Test always displays "This is not a number". It doesn't matter if I entered a or 1.
But if I order
echo... (2 Replies)
Hi,
I am trying to get the oracle variables and pass the values in sql placed in procedure.
VARIABLE
vstat='ASDS,FGDS,VCGD,VCXC'
Query :
select distinct dept from College
where section in ('C','D')
AND CODES =''
AND NAMES IN ('RAJ','SAM');
I want CODES values to be taken from vstat... (1 Reply)
Hello,
I have two files, f1 and f2. f1 has 5 columns like so:
a b c d 154
e f g h 365
.....
f2 has two columns, the first column contains the name of the above file and second column contains a constant which is to be used for division.
e.g.
file1 56
I want to divide the 5th... (2 Replies)
Discussion started by: Gussifinknottle
2 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)