How to use variables/array in grep command Post: 302273635

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Hi, There are total 100 files in the backup directory with the name format as below: prod_bkp_140611_13_30_05.txt prod_bkp_140611_14_30_05.txt prod_bkp_140611_15_30_05.txt prod_bkp_140611_16_30_05.txt How to use array variables (in perl) to get list of names of the above files ?

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Hi, everyone. I wrote a code like this for f in HB021* do program done for f in HB034* do program done for f in HB056* do program done . .

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zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)

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