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Full Discussion: quoting question
Top Forums Shell Programming and Scripting quoting question Post 302273545 by otheus on Monday 5th of January 2009 04:53:20 AM
Old 01-05-2009
Quote:
PS: in quoting as a reference i use chap7 from "learning the bash shell 3rd edition" but i am relatively new to shell scripting.Is there any other good reference for bash?
The "man" pages are a good reference.

You're right, by the way -- the * doesn't get expanded inside double-quotes. However, it's the ctags_command assignment that would give you problems:
Code:
ctags_command=echo separate words must be quoted

Here's another way to do it:
Code:
directory="~/project-dir"
file_locations=/home/work/folder[123]/*.sh
ctags_command="ctags $file_locations"

(cd "$directory" && $ctags_command )

Yet another way is with xargs:
Code:
directory="~/project-dir"
cd $directory && rm -f tags && find . -name "*.sh" | xargs ctags -a

The xargs command takes the output from find, and runs the ctags command as many times as needed (not once for each file, but as many times as required if the command line cannot hold all the arguments on one line). The -a command ensures ctags appends to the existing tags file in case xargs does need more than one call.
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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