hi gurus!
i realize that my question shows my stupidness, but i need your help!
i have:
s_date=`date +%m-%d-%Y_%I%p`
variable and i need the same, but minus one hour..
what i made:
s_date=time(`date +%m-%d-%Y_%I%p`) - 3600
but i'm getting:
daily_exports.sh: line 20: syntax error near... (4 Replies)
AWK subtraction in multiple columns
Hi there,
Can not get the following:
input: 34523 934
9485 3847
394 3847
3456 9384
awk 'NR==1 {for (i = 1; i <= NF; i++) {n=$i; next}; {n-=$i} END {print n}' input
output: 21188 first column only,... (2 Replies)
hi,
i set up a script on my server to do a particular task once files from an external system are ftpd in the format compaq_20100110 (YYDDMM). Interestingly, the source of ftp is sending the files in the format e.g 20100109 i.e. previous date and for some reason this fails.kindly see my script... (2 Replies)
Hallo all i am trying to execute this script ...............
But this is throwing the error......
use of uninitialized value in subtraction in at icd_convert.pl line 156
use of uninitialized value in subtraction in at icd_convert.pl line 157
use of uninitialized value in subtraction in at... (1 Reply)
FileA
F97S 83 530
K569E 531 736
output shud be
F16S
K40E
it is code
sed 's///g' FileA |awk '{print $1-$2+2}'
it will print
16
40
anything can come with this output?? (1 Reply)
Hi friends,
I have a file list1 which has these 2 columns like
616449 0
434453 1
2151083 0
2226536 0
2132382 0
2136814 0
I have to put the result of col1 -col2 into another file list2 linewise.
e.g. It gives the below result if use the below code:
awk '{ print $1 - $2 }' list1 >... (2 Replies)
Hi
#!/bin/sh
month=`date +%m`
year=`date +%Y`
echo $month
a=02
# Retaining Data for Current and Previous Month
lmonth=`expr $month - $a`
if test "$lmonth" = "0"
then
lmonth=12
year=`expr $year - 1`
fi
echo $year
echo $lmonth
The output is (3 Replies)
Hello all .
I have two arrays.
${ARRAY_MOUNT_POINT_CAPACITY}
${ARRAY_MOUNT_POINT_CAPACITY}.
Whats the synatx of subtracting their values , placing them in variable V1 and then echoeing it ???
Ive tried expr and let ...gives me ./test_code.sh: difference: bad number (3 Replies)
I have dates as follows in a file
20121029135649
20121029135721
20121030091540
20121030093420
20121030094340
20121030095427
20121030095856
20121030100104
20121030100251
All these dates are in sorted order. I need to find out the difference between the dates as follows
2nd row... (6 Replies)
Hello All,
I am a newbie to unix shell scripting and need to write a script that displays the difference between two variables that stores date value.
For example,
F1=`ls -ltr file1* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8`
F2=`ls -ltr file2* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8`
F1... (3 Replies)
Discussion started by: priyaa2010
3 Replies
LEARN ABOUT SUSE
xzdiff
XZDIFF(1) XZ Utils XZDIFF(1)NAME
xzcmp, xzdiff, lzcmp, lzdiff - compare compressed files
SYNOPSIS
xzcmp [cmp_options] file1 [file2]
xzdiff [diff_options] file1 [file2]
lzcmp [cmp_options] file1 [file2]
lzdiff [diff_options] file1 [file2]
DESCRIPTION
xzcmp and xdiff invoke cmp(1) or diff(1) on files compressed with xz(1), lzma(1), gzip(1), or bzip2(1). All options specified are passed
directly to cmp or diff. If only one file is specified, then the files compared are file1 (which must have a suffix of a supported com-
pression format) and file1 from which the compression format suffix has been stripped. If two files are specified, then they are uncom-
pressed if necessary and fed to cmp(1) or diff(1). The exit status from cmp or diff is preserved.
The names lzcmp and lzdiff are provided for backward compatibility with LZMA Utils.
SEE ALSO cmp(1), diff(1), xz(1), gzip(1), bzip2(1), zdiff(1)BUGS
Messages from the cmp(1) or diff(1) programs refer to temporary filenames instead of those specified.
Tukaani 2009-07-05 XZDIFF(1)