#! /bin/bash
head -5 $1
echo "remove $1 ?"
read answer
if
then
echo invalid answer
elif
rm $1
echo "$1 is deleted"
elif
then
echo file is not deleted
else
echo "invalid answer"
fi
What i really want this to do is to ask to delete the file or not..it says something wrong... (1 Reply)
#! /bin/bash
USAGE=" | ]
if
then
echo "$USAGE"
exit 1
fi
while getopts lb: OPTION
do
case $(OPTION)in
a) echo Hi there!
exit 2;;
b) echo hello
o) OARG=$OPTARG;;
\?)echo "$USAGE" ;;
exit 2;;
esac
done
shift `expr... (1 Reply)
I have four variables, dumpdata, defndata, compare1 and compare2
I want an IF statement condition which returns true when either dumpdata=defndata or (dumpdata<=compare1 and dumpdata>=compare2).
But this is not working for me..
if (4 Replies)
can anyone tell me why this code doesn't work how its supposed to, its the hangman game but it doesn't play how its supposed to
#!/bin/bash
NoAttempts="0"
livesgiven="5"
LivesRemain=$livesgiven
LettersAttempted=""
wordfile=words
numwords=0
function menu()
{
clear
cat << menu... (1 Reply)
Hi ,
iam new with sed command
D:\bfx_db>sed -ne '/^SP2-*:/S/^\<.*\.*\>$/\2\p' reg.sql >>D:\out.log
The filename, directory name, or volume label syntax is incorrect.
Here my source file is reg.sql , i need the output in out.log
Can anybody Help on this???? (4 Replies)
Hi all,
I have been given a task to search for strings in a file that is encoded. I need to display the file name only when all the 3 strings which i provide are present in the file name.
i first try to get a list of files according from the directory according to the value passed in argument... (0 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
ls -ld htdocs
drwxr-x--- 3 root root 8192 2006-11-19 10:41 htdocs
How would a host administrator... (1 Reply)
hi whats wrong in below??
CHECK=M10;
if ;
then
echo "hello hi";
else
echo "how are u hello hi";
fi
I am getting error as
./test.sh: line 2: '
./test.sh: line 2: M10: command not found
./test.sh: line 2: M10: command not found
./test.sh: line 2: M10: command not found (8 Replies)
Hi there,
i have a problem i have created followning sh files some years ago but now it dosen`t work anymore i never used it a long time. Can anyone find the Error? Its always runs the stop() block and trying to Killing the Server also if i try to start or creat a new one.
#!/bin/sh
stop()... (6 Replies)
Discussion started by: NewCannon
6 Replies
LEARN ABOUT DEBIAN
pmfunc
PMFUNC(1p) User Contributed Perl Documentation PMFUNC(1p)NAME
pmfunc - cat out a function from a module
DESCRIPTION
Given a fully-qualified function, this program opens up the file and attempts to cat out the source for that function.
EXAMPLES
$ pmfunc Cwd::getcwd
sub getcwd
{
abs_path('.');
}
RESTRICTIONS
Only subroutines that are defined in the normal fashion are seen, since a simple pattern-match is what does the extraction. Those loaded
other ways, such as via AUTOLOAD, typeglob aliasing, or in an "eval", will all necessarily be missed.
This is mostly here for people who are too lazy to type
sed '/^sub getcwd/,/}/p' `pmpath Cwd`
or
perl -ne 'print if /^subs+getcwd/ .. /}/' `pmpath Cwd`
RESTRICTIONS SEE ALSO AUTHORS and COPYRIGHTS
Copyright (C) 1999 Tom Christiansen.
Copyright (C) 2006-2008 Mark Leighton Fisher.
This is free software; you can redistribute it and/or modify it under the terms of either: (a) the GNU General Public License as published
by the Free Software Foundation; either version 1, or (at your option) any later version, or (b) the Perl "Artistic License". (This is the
Perl 5 licensing scheme.)
Please note this is a change from the original pmtools-1.00 (still available on CPAN), as pmtools-1.00 were licensed only under the Perl
"Artistic License".
perl v5.10.1 2010-02-22 PMFUNC(1p)