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Shell Programming and Scripting
Need help in sed command ( Replacing a pattern inside a file with a variable value )
Post 302270502 by frozensmilz on Monday 22nd of December 2008 05:40:02 AM
12-22-2008
Need help in sed command (using variable inside sed command)
Hello,
The below script is supposed to replace partition lines "//------" in a cpp source code. Based on the previous posts i changed the sed command accordingly. But now i am stuck up with another issue ....the sed command is found not accepting $x,$x before 's'. I gave the line number as such instead of $x and it worked.
Kindly help me in solving this problem. I want to change the multiple lines (line number given by $x from for loop) of a source file. strMatch is another script that returns a set of line numbers where the pattern is found.
srcCode=$1
parStr="//-----------------------------------------------------------------------------"
parStr="--- TESTING-BAS-BAS-TESTING ---"
linNum=`strMatch $1 "//----" | tr -d ':/-'`
for x in $linNum; do
cecho green "Replacing partition on line $x ..."
cat $1 | sed "$x,$xs+//---*+$parStr+g" > $1.tmp
done
exit
The below script is supposed to replace partition lines "//------" in a cpp source code. Based on the previous posts i changed the sed command accordingly. But now i am stuck up with another issue ....the sed command is found not accepting $x,$x before 's'. I gave the line number as such instead of $x and it worked.
Kindly help me in solving this problem. I want to change the multiple lines (line number given by $x from for loop) of a source file. strMatch is another script that returns a set of line numbers where the pattern is found.
srcCode=$1
parStr="//-----------------------------------------------------------------------------"
parStr="--- TESTING-BAS-BAS-TESTING ---"
linNum=`strMatch $1 "//----" | tr -d ':/-'`
for x in $linNum; do
cecho green "Replacing partition on line $x ..."
cat $1 | sed "$x,$xs+//---*+$parStr+g" > $1.tmp
done
exit
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LEARN ABOUT MINIX
grep
GREP(1) General Commands Manual GREP(1) NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)