12-17-2008
grep to show date/time of file the string was found in.
I've seen several examples of grep showing the filename the string was found in, but what I really need is grep to show the file details in long format (like ls -l would).
scenario is:
grep mobile_number todays_files
This will show me the string I'm after & which files they turn up in, but the string could show in several files, so being able to see the time the files were created & in time order would be handy in identifying the order of events rather than having to “ls -l” all the identified files after.
Eg
broken, still broken, fixed (good)
fixed, broken, still broken (bad)
I have tried combination of "-exec ls -ltr {} \;" but don't seem to be getting anywhere.
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)