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Full Discussion: Problem with assigning output of grep + awk to a variable
Top Forums Shell Programming and Scripting Problem with assigning output of grep + awk to a variable Post 302268620 by meheretoknow on Tuesday 16th of December 2008 03:40:09 AM
Old 12-16-2008
Hi ,

Thankyou...

The error was coming because of #!/bin/sh in the beginning of the script.

-----------------------
#!/bin/sh
whoami_code=$(grep `whoami` /etc/passwd | awk '{print $1}' | cut -d ":" -f3)
echo $whoami_code
--------------------------
When i removed that part it worked... is there any particular reason for that??
 

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       chdist - script to easily play with several distributions

SYNOPSIS

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DESCRIPTION

       chdist is a rewrite of what used to be known as 'MultiDistroTools' (or mdt). Its use is to create 'APT trees' for several distributions,
       making it easy to query the status of packages in other distribution without using chroots, for instance.

OPTIONS

       -h, --help
	   Provide a usage message.

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	   Choose data directory (default: $HOME/.chdist/).

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	   Choose architecture (default: `dpkg --print-architecture`).

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	   Display version information.

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	   List source package for BINPKG in DIST

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	   List versions of packages in several DISTributions

       compare-versions DIST1 DIST2
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	   Same as compare-packages/compare-bin-packages, but also runs dpkg --compare-versions and display where the package is newer.

       compare-src-bin-packages DIST
	   Compare sources and binaries for DIST

       compare-src-bin-versions DIST
	   Same as compare-src-bin-packages, but also run dpkg --compare-versions and display where the package is newer

       grep-dctrl-packages DIST [...]
	   Run grep-dctrl on *_Packages inside DIST

       grep-dctrl-sources DIST [...]
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       list
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