Hi All,
How can i use the cut option to only output the number of rows, which is 2 is this case ? Pls note that the number of digit before the delimiter ":" is always varying.
$ grep -n uuu xxx
2:** xxx yyy gg 44 tt uuu 2007
$ (2 Replies)
Hi
I tried to extract 19 characters (default) enclosed with in tag from a file using cut command. If the characters comprises of double space, the cut command gives the output with a single spacing.
file 1
<name>Kumar Rajasekaran</name>
cut -c7-26 "file1"
the out put i received is ... (48 Replies)
Is there a way to use a word as a delimiter with cut? Or is there a way to use sed or awk with a word as a delimiter? I don't care which program I use for a delimiter I just want to use a word as a delimiter. (2 Replies)
I need to cut or otherwise get the 4th and 5th position output of
for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done
example output is:
h;13;1310318701;443;93
I only need ";443;93" from any given run of "for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done"
Thanks... (3 Replies)
HI,
I have a file like below
"103865","103835","Zming","","Zhu","103965","Sunnyvale","US",
"116228","116227","Morlla","","Kowalski","113228","Paese "(Treviso)""IT"
I want to validate the 7th column which is below.
"Sunnyvale"
"Paese
In the above 7th column Paese is not ended with... (9 Replies)
Hi all,
I have a number of strings like below:
//mnt/autocor/43°13'(33")W/
and i'm trying to get the numbers in this string, for example
431333
please help
thanks ahead (14 Replies)
Hi there!
sed should cut of everything include the brackets
... 443,0.806362,0.67317,1.46563,14.8237(#/cm�)
... 5112,0.812411,0.67317,1.4831,14.1875(#/cm�)
it should be
... 443,0.806362,0.67317,1.46563,14.8237
... 5112,0.812411,0.67317,1.4831,14.1875
i try it several times with ...... (4 Replies)
i have list of names in a text file and I wanted to delete the commas en every line.
for example: inside the text is a list of names in it with commas after each line. I wanted to delete these commas. which command must I execute for this?
unix,
dale,
shawn,
aaron, (4 Replies)
Hi All-
We have a file data as below with delimiter as |#|
10|#|20|#|ABC
13|#|23|#|PBC
If I want to cut the 2nd field out of this, below command is not working as multiple pipe is causing an issue , it seems
cut -f2 -d"|#|" <file_name>
can you please help to provide the correct command... (7 Replies)