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Top Forums Shell Programming and Scripting Help on shell script : syntax error at line 62: `end of file' unexpected Post 302267292 by schandrakar1 on Friday 12th of December 2008 05:04:39 AM
Old 12-12-2008
Hi Zaxxon,

Thank you for your reply!!

What I meant is that the script contains total 61 lines ( ie first 11 lines are about the type of script, name, input parameter...etc...it is just description about the script.) The actual script starts from line number 12...Please see the actual code pasted below in set nu mode.

Also please refer to the debugged mode script pasted above.

Thanks a lot for your continued help!!


Code:
    12
    13  set -vx
    14
    15  ME_StaggCountry_Codes=$1
    16  Filename=`basename $0 .sh`
    17  LOGPATH=${HOME}/sandeep/camp/logs
    18  LOGFILE=${LOGPATH}/${Filename}_`date "+%d-%h-%Y_%T"`.log
    19
    20  exec 1> ${LOGFILE}
    21
    22  echo "`date "+%d-%h-%Y_%T"` : ----------- START of ${LOGFILE} ---------------" 2>&1
    23  echo
    24
    25  if [ $# -lt 1 ] || [ $# -gt 1 ] ; then
    26          echo "Invalid Parameter list"  2>&1
    27          echo "Usage : $0 <ME_StaggCountry_codes>" 2>&1
    28          echo
    29          echo "`date "+%d-%h-%Y_%T"` : ----------- END of ${LOGFILE} ---------------" 2>&1
    30          exit 1
    31  elif [ $# -eq 1 ] ; then
    32          echo "Input parameter file is : ${ME_StaggCountry_Codes}" 2>&1
    33  fi
    34
    35  for code in `cat ${ME_StaggCountry_Codes}`
    36  do
    37          if [ ${code} != uk ] ; then
    38                  Filepath=/${code}rtlftp01/logs
    39          elif [ ${code} = uk ] ; then
    40                  Filepath=/rtlftp01/logs
    41          fi
    42          echo
    43          echo "For Country : ${code}     2>&1
    44          echo "Truncate Files at path ${Filepath} are :" 2>&1
    45          ls -ltr ${Filepath}/trunc*  2>&1
    46          echo
    47          echo "Monthly files at path ${Filepath} are :" 2>&1
    48          ls -ltr ${Filepath}/monthly_mi*  2>&1
    49          echo
    50          echo "-----------------------" 2>&1
    51  done
    52  echo
    53  echo "`date "+%d-%h-%Y_%T"` : ----------- Removing old log files ---------------" 2>&1
    54
    55  find ${LOGPATH} -type f -name "${Filename}*.log" -mtime +2  | while read FILE
    56  do
    57          rm -i ${FILE} </dev/tty
    58  done
    59
    60  echo "`date "+%d-%h-%Y_%T"` : ----------- END of ${LOGFILE} ---------------" 2>&1
    61  exec >/dev/tty


Last edited by zaxxon; 12-12-2008 at 08:58 AM.. Reason: Close one, I removed the blanks in the tags
 

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ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
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