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Top Forums Shell Programming and Scripting piping output from PHP file into variable Post 302265915 by daydreamer on Monday 8th of December 2008 08:28:39 PM
Old 12-08-2008
piping output from PHP file into variable

Hi.

I have a script like so:
Code:
#!/bin/bash

download='php /var/www/last.php'
echo $download
if $download

How do I pipe the output of the php file into a variable, as when i run the if statement, it just echos the file output to the screen and does not actually consider the output (it will be either a 1 or 0).

Thanks.
 

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php-config(1)							Scripting Language						     php-config(1)

NAME
php-config - get information about PHP configuration and compile options SYNOPSIS
php-config [options] DESCRIPTION
php-config is a simple shell script for obtaining information about installed PHP configuration. OPTIONS
--prefix Directory prefix where PHP is installed, e.g. /usr/local --includes List of -I options with all include files --ldflags LD Flags which PHP was compiled with --libs Extra libraries which PHP was compiled with --extension-dir Directory where extensions are searched by default --include-dir Directory prefix where header files are installed by default --php-binary Full path to php CLI or CGI binary --php-sapis Show all SAPI modules available --configure-options Configure options to recreate configuration of current PHP installation --version PHP version --vernum PHP version as integer SEE ALSO php(1) VERSION INFORMATION
This manpage describes php, version 5.3.2. COPYRIGHT
Copyright (C) 1997-2006 The PHP Group This source file is subject to version 3.01 of the PHP license, that is bundled with this package in the file LICENSE, and is available through the world-wide-web at the following url: http://www.php.net/license/3_01.txt If you did not receive a copy of the PHP license and are unable to obtain it through the world-wide-web, please send a note to license@php.net so we can mail you a copy immediately. The PHP Group 2006 php-config(1)
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