12-08-2008
perl -p -i -e 's/original text string/replacementstring/g' file
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1. Shell Programming and Scripting
Hi,
i call my shell like:
my_shell "my project name"
my script:
#!/bin/bash -vx
projectname=$1
sed s/'PROJECT_NAME ='/'PROJECT_NAME = '$projectname/ <test_config_doxy >temp
cp temp test_config_doxy
the following error occurres:
sed s/'PROJECT_NAME ... (2 Replies)
Discussion started by: vivelafete
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2. AIX
I was trying to replace a string ( for eg - @@asterisk@@ to * ) in variable using
cat $INFILE | while read LINE
do
stmt1=`echo $LINE | sed 's/@@asterisk@@/\*/g'`
stmt=$stmt' '$stmt1
stmt2=`echo $LINE`
STATEMENT=$STATEMENT' '$stmt2
done
echo 'Statement with sed -- > '... (5 Replies)
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3. Shell Programming and Scripting
e.g.
/home/$USER/.config replace it with "" (empty)
Is this possible?
I think you should play a bit with sharps ## and sed:b: (2 Replies)
Discussion started by: hakermania
2 Replies
4. Shell Programming and Scripting
Hi Fellows,
I am new to shell, please help we me out in this..
i have file which some lines like this..
$$param1='12-jan-2011'
$$param2='14-jan-2011'
$$param3='30-jan-2011'
.
.
.....so on..
I want to change $$param3 to '31-dec-2011'. i have variable which is storing(30-jan-2011 this... (1 Reply)
Discussion started by: victor369
1 Replies
5. Shell Programming and Scripting
Can someone tell me how I can do this?
e.g:
a=$(echo -e wert trewt ertert ertert ertert erttert
erterte
rterter
tertertert
ert)
How do i replace the STRING with $a?
I try this:
sed -i 's/STRING/'"$a"'/g' filename.ext
but this don' t work (2 Replies)
Discussion started by: jforce
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6. Shell Programming and Scripting
I have a file having some text like:
PATH_ABC=/user/myLocation
I have to replace "/user/myLocation" with a session variable say, $REPLACE_PATH,
where $REPLACE_PATH=/user/myReplaceLocation
The following sed command is not working. It is writing PATH_ABC=$REPLACE_PATH in the file
... (2 Replies)
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Hi All, Hoping someone can help....
I am trying to work out how I can ammend a log file to remove variable strings in order to remove confidential information which I cant pass on.
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My sample file is variable length, with out any field delimiters. It has min of 18 chars length and the 'CRLF' is potentially between 12-14 chars. How do I replace this with a space? I still want to keep end of record, but just want to remove these new lines chars in the middle of the data.
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9. Shell Programming and Scripting
Hi,
Wish to remove "DR-" from the string variable (var).
var="DR-SERVER1"
var=`echo $var | sed -e 's/DR-//g'`
echo "$var"
Expected Output:
However, I get the below error:
Can you please suggest. (4 Replies)
Discussion started by: mohtashims
4 Replies
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Hello,
I have simple while and for loops in a shell script and I would like to replace some characters in COL2 when I run it. I am on ubuntu 14.04
while read COL1 COL2 COL3 COL4
do
name=$COL2
#cat $name | sed -i "s|_| |g" $name
for i in $COL3 $COL4
do
some codes ...... run $i b="$name"... (11 Replies)
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LEARN ABOUT DEBIAN
mail::message::construct::text
Mail::Message::Construct::Text(3pm) User Contributed Perl Documentation Mail::Message::Construct::Text(3pm)
NAME
Mail::Message::Construct::Text - capture a Mail::Message as text
SYNOPSIS
my $text = $msg->string;
my $text = "$msg"; # via overload
my @text = $msg->lines;
my @text = @$lines; # via overload
my $fh = $msg->file;
my $line = <$fh>;
$msg->printStructure;
DESCRIPTION
Complex functionality on Mail::Message objects is implemented in different files which are autoloaded. This file implements the
functionality related to creating message replies.
METHODS
The whole message as text
$obj->file()
Returns the message as file-handle.
$obj->lines()
Returns the whole message as set of lines. In LIST context, copies of the lines are returned. In SCALAR context, a reference to an
array of lines is returned.
$obj->printStructure([FILEHANDLE|undef],[INDENT])
Print the structure of a message to the specified FILEHANDLE or the selected filehandle. When explicitly "undef" is specified as
handle, then the output will be returned as string.
The message's subject and the types of all composing parts are displayed.
INDENT specifies the initial indentation string: it is added in front of each line. The INDENT must contain at least one white-space.
example:
my $msg = ...;
$msg->printStructure(*OUTPUT);
$msg->printStructure;
my $struct = $msg->printStructure(undef);
# Possible output for one message:
multipart/mixed: forwarded message from Pietje Puk (1550 bytes)
text/plain (164 bytes)
message/rfc822 (1043 bytes)
multipart/alternative: A multipart alternative (942 bytes)
text/plain (148 bytes, deleted)
text/html (358 bytes)
$obj->string()
Returns the whole message as string.
Flags
SEE ALSO
This module is part of Mail-Box distribution version 2.105, built on May 07, 2012. Website: http://perl.overmeer.net/mailbox/
LICENSE
Copyrights 2001-2012 by [Mark Overmeer]. For other contributors see ChangeLog.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. See
http://www.perl.com/perl/misc/Artistic.html
perl v5.14.2 2012-05-07 Mail::Message::Construct::Text(3pm)