Sponsored Content
Top Forums Shell Programming and Scripting Replace string in a file w/ a variable value Post 302265896 by tret on Monday 8th of December 2008 06:05:17 PM
Old 12-08-2008
Ok so the following works...... almost

Code:
cat sample.txt | sed -e 's/abc/xyz/' >> result.txt

The only problem is, I want to use variables instead of abc and xyz

so something like

Code:
SEARCH="REPLACETHISTEXT"
REPLACE="Hello"

cat sample.txt | sed -e 's/$SEARCH/$REPLACE/' >> result.txt

When I try this, nothing happens, are the variables not available due to the pipe? Is there a way around this?

Thanks,
Rob
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Using sed to replace a string in file with a string in a variable that contains spaces

Hi, i call my shell like: my_shell "my project name" my script: #!/bin/bash -vx projectname=$1 sed s/'PROJECT_NAME ='/'PROJECT_NAME = '$projectname/ <test_config_doxy >temp cp temp test_config_doxy the following error occurres: sed s/'PROJECT_NAME ... (2 Replies)
Discussion started by: vivelafete
2 Replies

2. AIX

Replace string with asterisk(*) in variable

I was trying to replace a string ( for eg - @@asterisk@@ to * ) in variable using cat $INFILE | while read LINE do stmt1=`echo $LINE | sed 's/@@asterisk@@/\*/g'` stmt=$stmt' '$stmt1 stmt2=`echo $LINE` STATEMENT=$STATEMENT' '$stmt2 done echo 'Statement with sed -- > '... (5 Replies)
Discussion started by: Vaddadi
5 Replies

3. Shell Programming and Scripting

Find and replace string from file which contains variable and path - SH

e.g. /home/$USER/.config replace it with "" (empty) Is this possible? I think you should play a bit with sharps ## and sed:b: (2 Replies)
Discussion started by: hakermania
2 Replies

4. Shell Programming and Scripting

Replace string in file with a variable value

Hi Fellows, I am new to shell, please help we me out in this.. i have file which some lines like this.. $$param1='12-jan-2011' $$param2='14-jan-2011' $$param3='30-jan-2011' . . .....so on.. I want to change $$param3 to '31-dec-2011'. i have variable which is storing(30-jan-2011 this... (1 Reply)
Discussion started by: victor369
1 Replies

5. Shell Programming and Scripting

replace (sed?) a string in file with multiple lines (string) from variable

Can someone tell me how I can do this? e.g: a=$(echo -e wert trewt ertert ertert ertert erttert erterte rterter tertertert ert) How do i replace the STRING with $a? I try this: sed -i 's/STRING/'"$a"'/g' filename.ext but this don' t work (2 Replies)
Discussion started by: jforce
2 Replies

6. Shell Programming and Scripting

How to replace a string with a variable in a file using sed?

I have a file having some text like: PATH_ABC=/user/myLocation I have to replace "/user/myLocation" with a session variable say, $REPLACE_PATH, where $REPLACE_PATH=/user/myReplaceLocation The following sed command is not working. It is writing PATH_ABC=$REPLACE_PATH in the file ... (2 Replies)
Discussion started by: SKhan
2 Replies

7. UNIX for Dummies Questions & Answers

Replace variable string with text

Hi All, Hoping someone can help.... I am trying to work out how I can ammend a log file to remove variable strings in order to remove confidential information which I cant pass on. As an example I have used phone numbers. A large log file contains multiple lines containing something like the... (6 Replies)
Discussion started by: mutley2202
6 Replies

8. UNIX for Beginners Questions & Answers

Views How to replace a CRLF char from a variable length file in the middle of a string in UNIX?

My sample file is variable length, with out any field delimiters. It has min of 18 chars length and the 'CRLF' is potentially between 12-14 chars. How do I replace this with a space? I still want to keep end of record, but just want to remove these new lines chars in the middle of the data. ... (7 Replies)
Discussion started by: chandrath
7 Replies

9. Shell Programming and Scripting

Replace substring from a string variable

Hi, Wish to remove "DR-" from the string variable (var). var="DR-SERVER1" var=`echo $var | sed -e 's/DR-//g'` echo "$var" Expected Output: However, I get the below error: Can you please suggest. (4 Replies)
Discussion started by: mohtashims
4 Replies

10. Shell Programming and Scripting

How to replace string in variable?

Hello, I have simple while and for loops in a shell script and I would like to replace some characters in COL2 when I run it. I am on ubuntu 14.04 while read COL1 COL2 COL3 COL4 do name=$COL2 #cat $name | sed -i "s|_| |g" $name for i in $COL3 $COL4 do some codes ...... run $i b="$name"... (11 Replies)
Discussion started by: baris35
11 Replies
QSUBST(1)						    BSD General Commands Manual 						 QSUBST(1)

NAME
qsubst -- query-replace strings in files SYNOPSIS
qsubst str1 str2 [flags] file [file [...]] DESCRIPTION
qsubst reads its options (see below) to get a list of files. For each file on this list, it then replaces str1 with str2 wherever possible in that file, depending on user input (see below). The result is written back onto the original file. For each potential substitution found, the user is prompted with a few lines before and after the line containing the string to be substi- tuted. The string itself is displayed using the terminal's standout mode, if any. Then one character is read from the terminal. This is then interpreted as follows (this is designed to be like Emacs' query-replace-string): space Replace this occurrence and go on to the next one. . Replace this occurrence and don't change any more in this file (i.e., go on to the next file). , Tentatively replace this occurrence. The lines as they would look if the substitution were made are printed out. Then another character is read and it is used to decide the result as if the tentative replacement had not happened. n Don't change this one; just go on to the next one. ^G Don't change this one or any others in this file, but instead simply go on to the next file. ! Change the rest in this file without asking, then go on to the next file (at which point qsubst will start asking again). ? Print out the current filename and ask again. The first two arguments to qsubst are always the string to replace and the string to replace it with. The options are as follows: -w The search string is considered as a C symbol; it must be bounded by non-symbol characters. This option toggles. ('w' for 'word'.) -! -go -noask Enter ! mode automatically at the beginning of each file. -nogo -ask Negate -go, that is, ask as usual. -cN (Where N is a number.) Give N lines of context above and below the line with the match when prompting the user. -CAN (Where N is a number.) Give N lines of context above the line with the match when prompting the user. -CBN (Where N is a number.) Give N lines of context below the line with the match when prompting the user. -f filename The filename argument is one of the files qsubst should perform substitutions in. -F filename qsubst reads filename to get the names of files to perform substitutions in. The names should appear one to a line. The default amount of context is -c2, that is, two lines above and two lines below the line with the match. Arguments not beginning with a - sign in the options field are implicitly preceded by -f. Thus, -f is really needed only when the file name begins with a - sign. qsubst reads its options in order and processes files as it gets them. This means, for example, that a -go will affect only files named after the -go. The most context you can get is ten lines each, above and below. str1 is limited to 512 characters; there is no limit on the size of str2. Neither one may contain a NUL. NULs in the file may cause qsubst to make various mistakes. If any other program modifies the file while qsubst is running, all bets are off. AUTHORS
der Mouse <mouse@rodents.montreal.qc.ca> BSD
September 4, 1999 BSD
All times are GMT -4. The time now is 07:00 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy