Hi,
i call my shell like:
my_shell "my project name"
my script:
#!/bin/bash -vx
projectname=$1
sed s/'PROJECT_NAME ='/'PROJECT_NAME = '$projectname/ <test_config_doxy >temp
cp temp test_config_doxy
the following error occurres:
sed s/'PROJECT_NAME ... (2 Replies)
I was trying to replace a string ( for eg - @@asterisk@@ to * ) in variable using
cat $INFILE | while read LINE
do
stmt1=`echo $LINE | sed 's/@@asterisk@@/\*/g'`
stmt=$stmt' '$stmt1
stmt2=`echo $LINE`
STATEMENT=$STATEMENT' '$stmt2
done
echo 'Statement with sed -- > '... (5 Replies)
Hi Fellows,
I am new to shell, please help we me out in this..
i have file which some lines like this..
$$param1='12-jan-2011'
$$param2='14-jan-2011'
$$param3='30-jan-2011'
.
.
.....so on..
I want to change $$param3 to '31-dec-2011'. i have variable which is storing(30-jan-2011 this... (1 Reply)
Can someone tell me how I can do this?
e.g:
a=$(echo -e wert trewt ertert ertert ertert erttert
erterte
rterter
tertertert
ert)
How do i replace the STRING with $a?
I try this:
sed -i 's/STRING/'"$a"'/g' filename.ext
but this don' t work (2 Replies)
I have a file having some text like:
PATH_ABC=/user/myLocation
I have to replace "/user/myLocation" with a session variable say, $REPLACE_PATH,
where $REPLACE_PATH=/user/myReplaceLocation
The following sed command is not working. It is writing PATH_ABC=$REPLACE_PATH in the file
... (2 Replies)
Hi All, Hoping someone can help....
I am trying to work out how I can ammend a log file to remove variable strings in order to remove confidential information which I cant pass on.
As an example I have used phone numbers. A large log file contains multiple lines containing something like the... (6 Replies)
My sample file is variable length, with out any field delimiters. It has min of 18 chars length and the 'CRLF' is potentially between 12-14 chars. How do I replace this with a space? I still want to keep end of record, but just want to remove these new lines chars in the middle of the data.
... (7 Replies)
Hi,
Wish to remove "DR-" from the string variable (var).
var="DR-SERVER1"
var=`echo $var | sed -e 's/DR-//g'`
echo "$var"
Expected Output:
However, I get the below error:
Can you please suggest. (4 Replies)
Hello,
I have simple while and for loops in a shell script and I would like to replace some characters in COL2 when I run it. I am on ubuntu 14.04
while read COL1 COL2 COL3 COL4
do
name=$COL2
#cat $name | sed -i "s|_| |g" $name
for i in $COL3 $COL4
do
some codes ...... run $i b="$name"... (11 Replies)
Discussion started by: baris35
11 Replies
LEARN ABOUT LINUX
gnomevfs-cat
gnomevfs-cat(1) User Commands gnomevfs-cat(1)NAME
gnomevfs-cat - print a file to standard output using the VFS system
SYNOPSIS
gnomevfs-cat URI
DESCRIPTION
gnomevfs-cat prints a file to standard output using the virtual file system to access the file via a URI.
OPERANDS
The following operands are supported:
URI Specifies the file location in standard URI format.
EXAMPLES
Example 1: Cat a File From a Web Server
example% gnomevfs-cat http://www.sun.com
Example 2: Cat a Local File
example% gnomevfs-cat file:///home/user/README.txt
ENVIRONMENT VARIABLES
See environ(5) for descriptions of the following environment variables: NLSPATH.
EXIT STATUS
The exit value 0 is returned regardless of success or failure.
FILES
The following files are used by this application:
/usr/bin/gnomevfs-cat Executable to print a file to standard output using the VFS system
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWgnome-vfs |
+-----------------------------+-----------------------------+
|Interface stability |External |
+-----------------------------+-----------------------------+
SEE ALSO gnomevfs-copy(1), gnomevfs-info(1), gnomevfs-ls(1), gnomevfs-mkdir(1)NOTES
Written by Stephen Browne, Sun Microsystems Inc., 2004.
SunOS 5.10 6 Sep 2004 gnomevfs-cat(1)