echo 'This "sentence is" a combination of "multiple words"' | nawk -f garric.awk
garric.awk:
Code:
# setcsv(str, sep) - parse CSV (MS specification) input
# str, the string to be parsed. (Most likely $0.)
# sep, the separator between the values.
#
# After a call to setcsv the parsed fields are found in $1 to $NF.
# setcsv returns 1 on sucess and 0 on failure.
#
# By Peter Str\366mberg aka PEZ.
# Based on setcsv by Adrian Davis. Modified to handle a separator
# of choice and embedded newlines. The basic approach is to take the
# burden off of the regular expression matching by replacing ambigious
# characters with characters unlikely to be found in the input. For
# this the characters "\035".
#
# Note 1. Prior to calling setcsv you must set FS to a character which
# can never be found in the input. (Consider SUBSEP.)
# Note 2. If setcsv can't find the closing double quote for the string
# in str it will consume the next line of input by calling
# getline and call itself until it finds the closing double
# qoute or no more input is available (considered a failiure).
# Note 3. Only the "" representation of a literal quote is supported.
# Note 4. setcsv will probably missbehave if sep used as a regular
# expression can match anything else than a call to index()
# would match.
BEGIN { FS=SUBSEP; OFS="|" }
{
result = setcsv($0, " ")
for(i=1;i<=NF;i++)
printf("result[%d] = %s\n", i-1, $i)
#print
}
function setcsv(str, sep, i) {
gsub(/""/, "\035", str)
gsub(sep, FS, str)
while (match(str, /"[^"]*"/)) {
middle = substr(str, RSTART+1, RLENGTH-2)
gsub(FS, sep, middle)
str = sprintf("%.*s%s%s", RSTART-1, str, middle,
substr(str, RSTART+RLENGTH))
}
if (index(str, "\"")) {
return ((getline) > 0) ? setcsv(str (RT != "" ? RT : RS) $0, sep) : !setcsv(str "\"", sep)
} else {
gsub(/\035/, "\"", str)
$0 = str
for (i = 1; i <= NF; i++)
if (match($i, /^"+$/))
$i = substr($i, 2)
$1 = $1 ""
return 1
}
}
Dear all,
One of our jobs retrieves data from tables and writes it to files. This job was running for around 15 minutes for the past 8 months. Now, this job is runnig for 45-50 minutes. I checked with the DBA's and found no issues with database. The time taken by to job to write to the file is... (5 Replies)
Hi ,
I want gzip a folder te55 which has got 3 files test1.test2,test3
the name of the gzipped folder should be te55.gz with the 3 files as test1,test2,test3 itself...
Is it possible...
thanks in advance
sam (5 Replies)
HI
system.sysUpTime.0 : Timeticks: (1519411311) 175 days, 20:35:13.11
From the above output i need only 175days in a perl script..
Please Help (2 Replies)
Hi all,
I am trying to send a mail by using MAILX option to my YAHOO-Id.
It is giving the following error. Can any one help me to find what is the problem? Do i need to get any kind of settings in my UNIX box for using MAILX?
The bounce mail is as below:
Message 1:
From MAILER-DAEMON Tue... (2 Replies)
Hi Guys,
I have a doubt either to Reboot the server after Replacing the disk0.
I have two disks under vxvm root mirrored and i had a problem with primary disk so i replace the disk0 failed primary disk and then mirrored. After mirroring is it reboot required ? (7 Replies)
Hi masters,
I have one doubt,
lets's say file1 has the following contents,
1
2.0
3.1
5.5
7
5.10
5.9
How to sort these contents to get the o/p like
1
2.0
3.1
5.5
5.9
5.10
7 (8 Replies)
Since I cannot find a ffmpeg build that will automatically include a environment variable for the CMD ffmpeg command I'll probably have to do it myself.
However I would like to do so by saving it inside a .reg file.
For example if my path towards FFMPEG is:
C:\RESOURCE\FFMPEG\ffmpeg.exe
... (5 Replies)
Need your help in creating regular expression for particular set. let say I have given two dates 20130623 to 20140625.
I need to create regular for the dates which fall in between above two dates. (4 Replies)
Discussion started by: gvkumar25
4 Replies
LEARN ABOUT NETBSD
strtok_r
STRTOK(3) BSD Library Functions Manual STRTOK(3)NAME
strtok, strtok_r -- string tokens
LIBRARY
Standard C Library (libc, -lc)
SYNOPSIS
#include <string.h>
char *
strtok(char * restrict str, const char * restrict sep);
char *
strtok_r(char *str, const char *sep, char **lasts);
DESCRIPTION
The strtok() function is used to isolate sequential tokens in a nul-terminated string, str. These tokens are separated in the string by at
least one of the characters in sep. The first time that strtok() is called, str should be specified; subsequent calls, wishing to obtain
further tokens from the same string, should pass a null pointer instead. The separator string, sep, must be supplied each time, and may
change between calls.
The strtok() function returns a pointer to the beginning of each subsequent token in the string, after replacing the separator character
itself with a NUL character. Separator characters at the beginning of the string or at the continuation point are skipped so that zero
length tokens are not returned. When no more tokens remain, a null pointer is returned.
The strtok_r() function implements the functionality of strtok() but is passed an additional argument, lasts, which points to a user-provided
pointer which is used by strtok_r() to store state which needs to be kept between calls to scan the same string; unlike strtok(), it is not
necessary to limit tokenizing to a single string at a time when using strtok_r().
EXAMPLES
The following will construct an array of pointers to each individual word in the string s:
#define MAXTOKENS 128
char s[512], *p, *tokens[MAXTOKENS];
char *last;
int i = 0;
snprintf(s, sizeof(s), "cat dog horse cow");
for ((p = strtok_r(s, " ", &last)); p;
(p = strtok_r(NULL, " ", &last)), i++) {
if (i < MAXTOKENS - 1)
tokens[i] = p;
}
tokens[i] = NULL;
That is, tokens[0] will point to "cat", tokens[1] will point to "dog", tokens[2] will point to "horse", and tokens[3] will point to "cow".
SEE ALSO index(3), memchr(3), rindex(3), strchr(3), strcspn(3), strpbrk(3), strrchr(3), strsep(3), strspn(3), strstr(3)STANDARDS
The strtok() function conforms to ANSI X3.159-1989 (``ANSI C89''). The strtok_r() function conforms to IEEE Std 1003.1c-1995 (``POSIX.1'').
BUGS
The System V strtok(), if handed a string containing only delimiter characters, will not alter the next starting point, so that a call to
strtok() with a different (or empty) delimiter string may return a non-NULL value. Since this implementation always alters the next starting
point, such a sequence of calls would always return NULL.
BSD August 11, 2002 BSD