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Full Discussion: Pointer to a struct (with pointers) *** glibc detected *** double free
Top Forums Programming Pointer to a struct (with pointers) *** glibc detected *** double free Post 302263166 by jatoo on Monday 1st of December 2008 02:08:15 AM
Old 12-01-2008
Pointer to a struct (with pointers) *** glibc detected *** double free
I am using a structure defined as follows

Code:
struct gene_square
{
    double *x;
    double *y;
};

I have class, with a member function which is a pointer of this type:

Code:
gene_square* m_Genes;

I am allocating memory in the constructors like this:

Code:
m_Genes = new gene_square[square_genome_size];
    for (ii=0; ii<square_genome_size; ii++)
    {
        (m_Genes+ii)->x = new double[POINTS];
        (m_Genes+ii)->y = new double[POINTS];
    }

And my destructor does this:

Code:
if(m_Genes != NULL)
    {
        for(ii=0; ii<square_genome_size; ii++)
        {
            if (((m_Genes+ii)->x)!=NULL)
            {
                delete [] (m_Genes+ii)->x;
            }
            if (((m_Genes+ii)->y)!= NULL)
            {    
                delete [] (m_Genes+ii)->y;
            }
        }
        delete [] m_Genes;
    }

But when the destructor is called I am getting a glibc double free error.

Code:
*** glibc detected *** ./Evolution: double free or corruption (fasttop): 0x08055008 ***

And I can't work it out.

Anyone able to help?
 

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   double = $matrix->xy ($new)
       o   $new (double)

   double = $matrix->y0 ($new)
       o   $new (double)

   double = $matrix->yx ($new)
       o   $new (double)

   double = $matrix->yy ($new)
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