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Special Forums UNIX Desktop Questions & Answers Quick if file exist question... Post 302262970 by elbombillo on Saturday 29th of November 2008 11:28:39 PM
Old 11-30-2008
Quick if file exist question...

What does the "!" do in the second statement? Is kinda strange but sometimes one or the other works.

rsakey="~/.ssh/id_rsa.pub"

if [ -f $rsakey ];then
if [! -f $rsakey ];then
 

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SSH2_AUTH_PUBKEY_FILE(3)						 1						  SSH2_AUTH_PUBKEY_FILE(3)

ssh2_auth_pubkey_file - Authenticate using a public key

SYNOPSIS
bool ssh2_auth_pubkey_file (resource $session, string $username, string $pubkeyfile, string $privkeyfile, [string $passphrase]) DESCRIPTION
Authenticate using a public key read from a file. PARAMETERS
o $session - An SSH connection link identifier, obtained from a call to ssh2_connect(3). o $username - o $pubkeyfile - The public key file needs to be in OpenSSH's format. It should look something like: ssh-rsa AAAAB3NzaC1yc2EAAA....NX6sqSnHA8= rsa-key-20121110 o $privkeyfile - o $passphrase - If $privkeyfile is encrypted (which it should be), the $passphrase must be provided. RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 Authentication using a public key <?php $connection = ssh2_connect('shell.example.com', 22, array('hostkey'=>'ssh-rsa')); if (ssh2_auth_pubkey_file($connection, 'username', '/home/username/.ssh/id_rsa.pub', '/home/username/.ssh/id_rsa', 'secret')) { echo "Public Key Authentication Successful "; } else { die('Public Key Authentication Failed'); } ?> NOTES
Note The underlying libssh library doesn't support partial auths very cleanly That is, if you need to supply both a public key and a password it will appear as if this function has failed. In this particular case a failure from this call may just mean that auth hasn't been completed yet. You would need to ignore this failure and continue on and call ssh2_auth_password(3) in order to complete authentication. PHP Documentation Group SSH2_AUTH_PUBKEY_FILE(3)
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