I customized emacs like crazy...I'm a big fan of macros, but I do a lot of work on the command line and for that I'd love to have this function/alias defined.
I tried defining this function:
but it doesn't work if the command you need to execute is longer than one word. For example:
outputs an unexpected newline error. I don't understand what's going on...maybe my understanding of the way bash interprets positional parameters is not quite up to par.
Hi,
I've a question on awk. In English I want to:
(a) open a file, (b) search through the file for records where length of field15 > 20 characters and (c) print out some fields in the record.
I've written the following and it works OK. The trouble is this will ALWAYS write out the column... (5 Replies)
Hello I have the following awk script:
BEGIN {
{FS = " " }
{print "\t\tIllegal Loggon Attempts on MAIL\n"}
{"date" | getline d}
{printf "\t %s\n",d }
{print "Loggon Name\t\t\t Number of Attempts\n"}
... (2 Replies)
I am beginner in awk
awk 'BEGIN{for(i=1;(getline<"opnoise")>0;i++) arr=$1}{print arr}'
In the above script, opnoise is a file, I am reading it into an array and then printing the value corresponding to index 20. Well this is not my real objective, but I have posted this example to describe... (1 Reply)
I'm new to awk, trying to understand the basics.
I'm trying to reset the counter everytime the program gets a new file to check.
I figured in the BEGIN part it would work, but it doesn't.
#!/bin/awk -f
BEGIN {counter=0}
{
sum=0
for ( i=1; i<=NF;... (1 Reply)
Hi,
I have written below script to begin if the line has n
#!/bin/ksh
/usr/xpg4/bin/awk {/ n / 'BEGIN {X = "01"; X = "02"; X = "03"; X = "04";
X = "05"; X = "06"; X = "07"; X = "08";
X ="09"; X = "10"; X = "11"; X = "12"; };}
NR > 1 {print $1 "\t" $5 "," X "," $6 " " $7}'} input.txt |... (9 Replies)
Hi folks,
I have a scenario to convert the update statements into insert statements using shell script (awk, sed...) or in database using regex.
I have a bunch of update statements with all columns in a file which I need to convert into insert statements.
UPDATE TABLE_A SET COL1=1 WHERE... (0 Replies)
My code fails to do anything if I've BEGIN block in it:
Run the awk script as:
awk -f ~/bin/sum_dupli_gene.awk make_gene_probe.txt
#!/usr/bin/awk -f
BEGIN {
print ARGV
#--loads of stuff
}
END{
#more stuff
} (14 Replies)
Hi there,
I'm working with file more than 400K lines, 60 columns. Column count is going to be multiple of 12: 60, 12, 72 or so.
NF/12 gives me on how many iterations I've to do to check certain value.
For example: 7, 14th if only 24 columns in file.
7th, 14th and 21st if 36 columns in... (6 Replies)
Hi,
diffcount=`awk 'BEGIN { while ( getline < "/scripts/matt/text.server1.reference" ) { arr++ } } { if (!( $0 in arr ) ) { print } }' $TMPDIR/$(basename $0 .sh) | wc -l`
if ]; then
OK="OK - No change in the interfaces status"
elif ]; then
DIFF=`awk 'BEGIN {... (4 Replies)
Discussion started by: nms
4 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)