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Top Forums Shell Programming and Scripting arrays not printing properly in bash Post 302258531 by npatwardhan on Friday 14th of November 2008 06:31:53 PM
Old 11-14-2008
arrays not printing properly in bash

hi guys,
i wrote this script and it takes some fields from a file and puts it into three different arrays. The first array works just fine but when I try to use the second array (ARRAY1) all i get is a blank value on the screen..

this works fine..i get ARRAY[9] value on the screen just fine
Code:
exec 10<io
while read LINE <&10; do
    ARRAY[$count]=$LINE
    ((count++))
done
echo Number of elements: ${#ARRAY[@]}
echo ${ARRAY[@]}
echo ${ARRAY[9]}
exec 10>&-

this does not work..it shows me blank value on the output
Code:
exec 10<io1
while read LINE <&10; do
    ARRAY1[$count]=$LINE
    ((count++))
done
echo Number of elements: ${#ARRAY1[@]}
echo ${ARRAY1[@]}
echo ${ARRAY1[1]}
exec 10>&-

echo ${ARRAY1[@]} shows all the elements just fine but echo ${ARRAY1[1]} shows a blank on the screen..
what is wrong here?
 

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ARRAY_REPLACE(3)							 1							  ARRAY_REPLACE(3)

array_replace - Replaces elements from passed arrays into the first array

SYNOPSIS
array array_replace (array $array1, array $array2, [array $...]) DESCRIPTION
array_replace(3) replaces the values of $array1 with values having the same keys in each of the following arrays. If a key from the first array exists in the second array, its value will be replaced by the value from the second array. If the key exists in the second array, and not the first, it will be created in the first array. If a key only exists in the first array, it will be left as is. If several arrays are passed for replacement, they will be processed in order, the later arrays overwriting the previous values. array_replace(3) is not recursive : it will replace values in the first array by whatever type is in the second array. PARAMETERS
o $array1 - The array in which elements are replaced. o $array2 - The array from which elements will be extracted. o $... - More arrays from which elements will be extracted. Values from later arrays overwrite the previous values. RETURN VALUES
Returns an array, or NULL if an error occurs. EXAMPLES
Example #1 array_replace(3) example <?php $base = array("orange", "banana", "apple", "raspberry"); $replacements = array(0 => "pineapple", 4 => "cherry"); $replacements2 = array(0 => "grape"); $basket = array_replace($base, $replacements, $replacements2); print_r($basket); ?> The above example will output: Array ( [0] => grape [1] => banana [2] => apple [3] => raspberry [4] => cherry ) SEE ALSO
array_replace_recursive(3), array_merge(3). PHP Documentation Group ARRAY_REPLACE(3)
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