Hi again,
Well, I'm sorry to say it, but that doesn't give the expected output, at least not on my machine. The columns don't line up. And he also wanted headers, which was the reason for either two printf statements in an awk program or other AWKward cats and whiles and echoes... a seemingly complicaticated way to do it.
If it wasn't for the headers, Danmeros original solution would still have been the most correct:
or even
I did an experiment: the latter is faster on my machine on small files (the actual content supplied by OP) but when the file is 100 times bigger the awk program is a lot faster, a 10th of the time. So the conclusion is that if You need a reason to go for a cup of cocoa, run the while loop. If You are anxious to get home at the end of the day, do the awk. It's several nanoseconds we're dealing with here dudes!
The point, in this case, is taking in the arguments with any program that ignores repeated whitespace and reformat it in the desired fashion. At least that's how I see it. And which I missed completely in my first attempts at cracking it, focusing on how to handle or convert whitespace.
Hi all!
Here is my problem :
$ more file
yougli:passwd:123456:3265:Yepa Yepo:/home/yougli:/bin/ksh
As you can see, in the field "information", there are two spaces between "Yepa" and "yepo".
My problem is :
$ PARAM='more file | cut -d":" -f5'
$ echo $PARAM
Yepa Yepo
Now i only... (2 Replies)
#!/usr/bin/bash
cat /etc/passwd | while read A
do
USER=`echo “$A” | cut -f 1 -d “:”`
echo “Found $USER”
done
This shell script should make USER = the first field of the first line of the file /etc/passwd
Eg:
adm
daemon
bob
jane
kev
etc ...
However USER=echo... (3 Replies)
hi ,
i used ls -ltr | cut -f 1 > \dev\tty
but all teh coulmns r getting printed instead of only one........how can i resolve this?
prob 2 :
wud be able start cutting from last field......supposing in the case of dyanmic list.i dunno the field number of last column.......so is... (3 Replies)
I am trying to take one part of my text from file and save it to variable $x
I tryed this...
x=`cut -c 6-9 $fajl`
my file looks like this
fajl:
21890001277 89386911 23638FBCDC 28EE01A1 0000 26855 124 244326
21890001277 89766911 23638FBCDC 28E021A1 0000 26557 134 684326
21890001277... (7 Replies)
I'm new to shell programming, and am having a problem in a (Korn) shell program, which boils down to this:
The program reads a record from an input file and then uses a series of
"cut" commands to break the record into parts and assign the parts to
variables. There are no delimiters in the... (2 Replies)
Hi
I have a strange problem when using cut command
when i am using the below command, it is working fine,I am getting the data in new file xyz.dat
cut -c 1-75 abc.dat > xyz.dat
when i am using the below command, I am getting the data in new file abc.dat , but empty file
cut -c 1-75... (4 Replies)
Hi!
I get a md5 hash of a file with this command:
openssl md5 /Users/me/MyLogo.png | cut -f 2 -d ' '
"cut" because I just want the hash. But there is a problem -> that doen't work with a path with spaces:
openssl md5 /Users/me/MyLogo 2.png | cut -f 2 -d ' '
The result is "2.png)=" ...... (1 Reply)
Hi Friend ,
i have one file say xyz.lst and it has content like
dn: cn=m.hariharan,cn=employee,cn=delhi circle,cn=users,dc=industowers,dc=c
dn: cn=ajay.jain,cn=employee,cn=gujarat circle,cn=users,dc=industowers,dc=com
dn: cn=ajitkumar.thakor,cn=employee,cn=gujarat... (4 Replies)
There is a text file in my project named as "mom.txt" in which i want to have contents like..................
LSCRM(Application Name):
1: This is my first application.
2: Today we did shell scripting automation for this app.
3: It was really a good fun in doing so.
4: Really good.| (Here i... (7 Replies)
Hi Everyone,
I have a very simple problem and i am stuck in that from last 8 days. I tried many attempts, googled my query but all in vain.
I have a text file named "test.txt"
In that suppose i have contents like:
Java:
1 Object oriented programming language
2 Concepts of Abstraction... (5 Replies)
Discussion started by: Abhijeet Anand
5 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)