alter database mount standby database
ALTER DATABASE RECOVER standby database
ALTER DATABASE RECOVER CONTINUE DEFAULT
Media Recovery Log /oracle/P03/oraarch/P03arch1_7314.dbf
ORA-279 signalled during: ALTER DATABASE RECOVER CONTINUE DEFAULT ...
ALTER DATABASE RECOVER CONTINUE DEFAULT
Media Recovery Log /oracle/P03/oraarch/P03arch1_7315.dbf
Hi everybody
for file in *
#Bash performs filename expansion
#+ on expressions that globbing recognizes.
do
output="`grep -n "$1" "$file"`"
echo "$file: `expr "$output" : '\(^.*$\)'`"
done
In the above bash script segment, I try to print just the first line of string named... (3 Replies)
Hi,
How do i Print anything after a ':'
Ex :
file1: 1235131(rs32553)
I want to print out "1235131(rs32553)"
how do i do it. I know we can do this using awk but looking for the right syntax.
Any help appreciated.
Thanks,
Ram (7 Replies)
I am on a Solaris 10 x86 system
sample code
before3
before2
before1
group
after1
after2
after3
I want to grab the second line above my regexp
regexp=group
I want to grab ONLY the before2 line
I have numerous sed and awk ways of grabbing X line below the regexp, but no luck... (1 Reply)
Hi all,
This should be very easy but I can't figure it out...
I have a file that looks like this:
@SRR057408.1 FW8Y5CK02R652T length=34
AGCAGTGGTATCAACGCAGAGTAAGCAGTGGTAT
+SRR057408.1 FW8Y5CK02R652T length=34
FIIHFF6666?=:88@@@BBD:::?@ABBAAA>8
@SRR057408.2 FW8Y5CK02TBMHV length=52... (1 Reply)
Hi,
I have a file, say files_list, as below (o/p of ls -R cmd)
$ cat files_list
/remote/dir/path/to/file:
sub-dir1
sub-dir2
sub-dir3
...
/remote/dir/path/to/file/sub-dir1:
remote_file1.csv.tgz
<blank line 1>
/remote/dir/path/to/file/sub-dir2:
remote_file2.csv.tgz
<blank... (3 Replies)
Hello all
According to the following file (orignal one contains 200x times the same structure...) I was wondering if someone could help me to print <byte>??</byte> values
example, running this script/command like
./script.sh xxapp
I would expect as output: 102 116 112
./script.sh xxapp2... (2 Replies)
Hi All
I'm trying to extract the line just above a regexp and all lines after this.
I'm currently doing this in two steps
sed -n -e "/^+---/{g;p;}" -e h oldfile.txt > modified.txt
sed -e "1,/^+---/d" -e "/^$/d" oldfile.txt >>modified.txt
Sample
sometext will be here
sometext will be... (3 Replies)
I'm looking for a way to print the 4th line back from a regular expression. Kind of like the below but it has to be the 4th line before the regexp.
Print the line immediately before regexp, but not the line containing the regexp.
sed -n '/regexp/{g;1!p;};h'
here is an example of logs(i... (11 Replies)
How to use regexp to print out repetitive pattern in awk?
$ awk '{print $0, "-\t-\t-\t-\t-\t-\t-\t-\t-\t-\t-\t-"}' output:
- - - - - - - - - - - -I tried following which does not give what I want, of course.
awk '{print $0, "-\t{11}-"}'
output:
- ... (10 Replies)
Hi All,
I need to print the characters in the previous line just before the regular expression match
Please have a look at the input file as attached
I need to match the regular expression ^ with the character of the previous like and also the pin numbers
and the output file should be like... (6 Replies)