Thanks for the feedback. Still not doing quite what I need. Here is a sample of the input. The first column has 12 characters with leading spaces. The last column is character #36.
Here is the expected output:
The suggested awk script is getting me closer, however that is why I was using the while loop, so that when the workunit was less than 100, it would put in the two extra spaces needed in the output. When the number was between 100 -199, it would put in the extra space. The awk needs to remove leading spaces as well, which is what my sed after the cut was trying to accomplish.
Once again, any help would be greatly appreciated.
Last edited by synergy_texas; 11-12-2008 at 07:12 PM..
Hi all!
Here is my problem :
$ more file
yougli:passwd:123456:3265:Yepa Yepo:/home/yougli:/bin/ksh
As you can see, in the field "information", there are two spaces between "Yepa" and "yepo".
My problem is :
$ PARAM='more file | cut -d":" -f5'
$ echo $PARAM
Yepa Yepo
Now i only... (2 Replies)
#!/usr/bin/bash
cat /etc/passwd | while read A
do
USER=`echo “$A” | cut -f 1 -d “:”`
echo “Found $USER”
done
This shell script should make USER = the first field of the first line of the file /etc/passwd
Eg:
adm
daemon
bob
jane
kev
etc ...
However USER=echo... (3 Replies)
hi ,
i used ls -ltr | cut -f 1 > \dev\tty
but all teh coulmns r getting printed instead of only one........how can i resolve this?
prob 2 :
wud be able start cutting from last field......supposing in the case of dyanmic list.i dunno the field number of last column.......so is... (3 Replies)
I am trying to take one part of my text from file and save it to variable $x
I tryed this...
x=`cut -c 6-9 $fajl`
my file looks like this
fajl:
21890001277 89386911 23638FBCDC 28EE01A1 0000 26855 124 244326
21890001277 89766911 23638FBCDC 28E021A1 0000 26557 134 684326
21890001277... (7 Replies)
I'm new to shell programming, and am having a problem in a (Korn) shell program, which boils down to this:
The program reads a record from an input file and then uses a series of
"cut" commands to break the record into parts and assign the parts to
variables. There are no delimiters in the... (2 Replies)
Hi
I have a strange problem when using cut command
when i am using the below command, it is working fine,I am getting the data in new file xyz.dat
cut -c 1-75 abc.dat > xyz.dat
when i am using the below command, I am getting the data in new file abc.dat , but empty file
cut -c 1-75... (4 Replies)
Hi!
I get a md5 hash of a file with this command:
openssl md5 /Users/me/MyLogo.png | cut -f 2 -d ' '
"cut" because I just want the hash. But there is a problem -> that doen't work with a path with spaces:
openssl md5 /Users/me/MyLogo 2.png | cut -f 2 -d ' '
The result is "2.png)=" ...... (1 Reply)
Hi Friend ,
i have one file say xyz.lst and it has content like
dn: cn=m.hariharan,cn=employee,cn=delhi circle,cn=users,dc=industowers,dc=c
dn: cn=ajay.jain,cn=employee,cn=gujarat circle,cn=users,dc=industowers,dc=com
dn: cn=ajitkumar.thakor,cn=employee,cn=gujarat... (4 Replies)
There is a text file in my project named as "mom.txt" in which i want to have contents like..................
LSCRM(Application Name):
1: This is my first application.
2: Today we did shell scripting automation for this app.
3: It was really a good fun in doing so.
4: Really good.| (Here i... (7 Replies)
Hi Everyone,
I have a very simple problem and i am stuck in that from last 8 days. I tried many attempts, googled my query but all in vain.
I have a text file named "test.txt"
In that suppose i have contents like:
Java:
1 Object oriented programming language
2 Concepts of Abstraction... (5 Replies)
Discussion started by: Abhijeet Anand
5 Replies
LEARN ABOUT ULTRIX
cut
cut(1) General Commands Manual cut(1)Name
cut - cut out selected fields of each line of a file
Syntax
cut -clist [file1 file2...]
cut -flist [-dchar] [-s] [file1 file2...]
Description
Use the command to cut out columns from a table or fields from each line of a file. The fields as specified by list can be fixed length,
that is, character positions as on a punched card (-c option), or the length can vary from line to line and be marked with a field delim-
iter character like tab (-f option). The command can be used as a filter. If no files are given, the standard input is used.
Use to make horizontal ``cuts'' (by context) through a file, or to put files together in columns. To reorder columns in a table, use and
Options
list Specifies ranges that must be a comma-separated list of integer field numbers in increasing order. With optional - indicates
ranges as in the -o option of nroff/troff for page ranges; for example, 1,4,7; 1-3,8; -5,10 (short for 1-5,10); or 3- (short
for third through last field).
-clist Specifies character positions to be cut out. For example, -c1-72 would pass the first 72 characters of each line.
-flist Specifies the fields to be cut out. For example, -f1,7 copies the first and seventh field only. Lines with no field delim-
iters are passed through intact (useful for table subheadings), unless -s is specified.
-dchar Uses the specified character as the field delimiter. Default is tab. Space or other characters with special meaning to the
shell must be quoted. The -d option is used only in combination with the -f option, according to XPG3 and SVID2/SVID3.
-s Suppresses lines with no delimiter characters. Unless specified, lines with no delimiters are passed through untouched.
Either the -c or -f option must be specified.
Examples
Mapping of user IDs to names:
cut -d: -f1,5 /etc/passwd
To set name to the current login name for the csh shell:
set name=`who am i | cut -f1 -d" "`
To set name to the current login name for the sh, sh5, and ksh shells:
name=`who am i | cut -f1 -d" "`
Diagnostics
"line too long" A line can have no more than 511 characters or fields.
"bad list for c/f option"
Missing -c or -f option or incorrectly specified list. No error occurs if a line has fewer fields than the list calls
for.
"no fields" The list is empty.
See Alsogrep(1), paste(1)cut(1)